Which is true given the linear equation below? 3x+4y=4
1 answer:
Answer:
y= −3/4x + 1
x= -4/3y + 4/3
Step-by-step explanation:
Let's solve for y.
3x+4y=4
Step 1: Add -3x to both sides.
3x+4y+−3x=4+−3x
4y=−3x+4
Step 2: Divide both sides by 4.
4y4=−3x+44
y=−34x+1
___________
Let's solve for x.
3x+4y=4
Step 1: Add -4y to both sides.
3x+4y+−4y=4+−4y
3x=−4y+4
Step 2: Divide both sides by 3.
3x3=−4y+43
x= -4/3y + 4/3
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<u>S</u><u>o</u><u>l</u><u>u</u><u>t</u><u>i</u><u>o</u><u>n</u><u>:</u>
Given that
- Ami's mass is 72 kg and
- Raphael's mass is 108 kg.
To write Ami’s mass as a fraction of Raphael's mass, we divide Ami's mass by Raphael's mass. So it is now .
However, there the fraction is not yet in its simplest form, so we have to extract common factors from both the numerator and the denominator:
- =
Therefore, Ami's mass is the mass of Raphael.
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