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N76 [4]
3 years ago
6

If its right i’ll give brainliest!!

Mathematics
1 answer:
inessss [21]3 years ago
7 0

Answer:

6.5

Step-by-step explanation:

Square 42

\sqrt{42}=6.48074....

rounded to the tenth is 6.5

Hope this helps!

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Me voy a comprar una barra de cortinas. Como vivo en un doceavo piso, me interesa saber cuál es la longitud máxima que puedo met
iren2701 [21]

Answer:

The maximum length of the bar I could fit in the elevator is 2.87 meters.

Step-by-step explanation:

<u><em>The question in English is</em></u>

I'm going to buy a curtain rod. Since I live on a twelfth floor, I'm interested in knowing the maximum length I can put in the elevator.

So I take out my pocket tape measure, which only measures up to a meter and I measure the floor which turns out to be a square of 1m x 1m, but for the height it doesn't give.

However, there's a sticker on the lift box that says it has a capacity of 2,500 litres.

With all this information, what is the maximum length of bar that would fit me in the elevator?

step 1

Find the height of the elevator

we know that

The elevator has a capacity of 2,500 litres.

1\ m^3=1,000\ L

so

2,500\ L=2.5\ m^3

The volume of the elevator is given by

V=Bh

where

B is the area of the base

h is the height of the elevator

we have

B=(1)(1)=1\ m^2\\V=2.5\ m^3

substitute

2.5=(1)h\\h=2.5\ m

step 2

Find the diagonal of the base of the elevator

Let

d ---> diagonal of the base of the elevator

Applying the Pythagorean Theorem

d^2=b^2+b^2

substitute

d^2=1^2+1^2

d=\sqrt{2}\ m

step 3

Find the diagonal of the rectangular prism (elevator)

Let

D ----> diagonal of the rectangular prism

d ---> diagonal of the base of elevator

h ----> height of the elevator

Applying the Pythagorean Theorem

D^2=d^2+h^2

substitute

D^2=(\sqrt{2})^2+2.5^2

D^2=8.25\\D=2.87\ cm

therefore

The maximum length of the bar I could fit in the elevator is 2.87 meters.

3 0
3 years ago
What is 23/20 as a mixed number
cupoosta [38]

Step-by-step explanation:

this is an improper fraction to make it mixed you have to find how many 20s are in 23

yea only one

so 1 is the whole number

then it is 1 3/20

you can again make it improper by multiplying denominator by 1 and adding 3

7 0
3 years ago
Read 2 more answers
The bank charged TENLEY $30 fee because her balance dropped below $0. She knows that she currently has an outstanding charge of
Korolek [52]

Answer:

Tenley has to deposited any amount from $50 and above.

Step-by-step explanation:

From the above question, we can deduce that if your bank balance is below 0, = - , you would be charged $30

Hence,

First she has to pay the bank charges of $30, and to prevent the outstanding charge of $19.95 for generating about charge she has to deposit any amount above $19.95

The amount she has to deposit is

$30 + (x > $19.95)

Assuming x is $20 and above

= $30 + $20 = $50

Hence, Tenley has to deposited any amount from $50 and above.

7 0
3 years ago
How do you find the least common multiple of 2 numbers? Preferably using the ladder method
g100num [7]
Hi,
Sorry, I don't use the ladder method, but I can show you how to find the <span>least common multiple of 2 numbers using a different method:
Let's say we are finding the least common multiple of 3 and 9:

3: 3, 6, 9, 12, 15, 18
            --
-------------------------------
9: 9, 18, 27, 36, 45, 54
    --

All I did was list multiples of both the numbers till I found one that was common (however, in the example above, I listed a few extra)

Hope this helped 
:)

</span>
8 0
3 years ago
X²-4=0 can you help me solve for x?​
Nana76 [90]

Answer:

  • x = 2 & - 2

Step-by-step explanation:

We have to find the value of x from the given equation.

  • x²-4=0 is a quadratic equation, so it will have two values.

Step: Write the equation in simplest form.

  • x²-4=0

Step: Solve the problem by spiltting method.

  • x² - 4 = 0
  • x² - (2)² = 0

Step: Solve the problem with using algebraic formula.

  • x² - 2² = 0
  • (x - 2)(x + 2) = 0

Step : We have used a²-b² to solve the problem.

  • (x - 2)(x + 2) = 0
  • (x - 2)(x + 2) = 0
  • (x - 2)=0 or (x + 2) = 0
  • x = 2 & - 2

Therefore, the possible values of x are 2 & - 2.

7 0
3 years ago
Read 2 more answers
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