Answer:
We have the system:
x ≤ 7
x ≥ a
Now we want to find the possible values of a such that the system has, at least, one solution.
First, we should look at the value of a where the system has only one solution:
We can write the 2 sets as:
a ≤ x
x ≥ 7
So, writing both together:
a ≤ x ≤ 7
if a is larger than 7, we do not have solutions.
then a = 7 gives:
7 ≤ x ≤ 7
Here the only solution is 7.
Now, if a is smaller than 7, for example 5, we have:
5 ≤ x ≤ 7
Now x can take different values, so we have a lot of solutions.
Then the restrictions for a, such that the system has at least one solution, is:
a ≤ 7.
Answer:
33 ft
Step-by-step explanation:
5.5/4 = x/24
x=33
The best thing to do is to rewrite the fractions as decimals
-2/3 is approx. equal to -0.6666667
So a little past half way (to the left) between -1 and 0
1 1/5 is 1.5 so that is right between 1 and 2
Hope this helps :)
16r^2+ 2r -4r
16r^2 - 2r
2r ( 8r -1)
Answer: 1, 3, 5, 7, 9, . . . . , 37. Therefore, 361 is the sum of first 19 odd numbers.
Step-by-step explanation:
