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3 years ago

Graph the line with slope -8 and y-intercept 9.

Mathematics

1 answer:

salantis [7]3 years ago

8 0

Answer:

the coordinates will be (0,9) (-8,0) and the equation will be y=(9/8x)+9

Step-by-step explanation:

Im not 100% sure but if im right please mark me as brainliest

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How many terms are in the expression 3x^2y^4z-6xy-3z(5x^2)

EleoNora [17]

I would say 3 because terms are separated by a plus or minus sign and there are 2 subtraction signs separating 3 expressions.

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3 years ago

What is the slope of the line passing through<br> points (6, -1) and (1,8)?

Fynjy0 [20]

Answer:

-1.8

Step-by-step explanation:

m= y2 - y2over x2 - x1

m= -1 - 8 over 1 - 6 = -1.8

m= -1.8

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3 years ago

Write an expression that is equivalent to - 0.5(14a - 22) .

PSYCHO15rus [73]

$\textsf{Hey \: there}$

<h2>QUESTION</h2>

$\mathsf{-0.5(14a - 22)}$

<h2>FIRST YOU HAVE TO DISTRIBUTE:</h2>

$\mathsf{(-0.5)(14a) + (-0.5)( -22)}$

<h2>SOLVING FOR OUR ANSWER</h2>

$\mathsf{(0.5)(14a) = - 7a} \\ \\ \mathsf{( - 0.5)( - 22) = 11}$

<h2 /><h2>NEW EQUATION/THE ANSWER YOU WERE LOOKING FOR </h2>

$\boxed{ \bf{your \: answer:} \boxed{ \huge \textsf{ \bf- 7a + 11}}} \checkmark$

<h2>GOOD LUCK ON YOUR ASSIGNMENT AND ENJOY YOUR DAY!</h2>

$\dfrac{\frak{LoveYourselfFirst}}{:)}$

<h2>SIDE NOTE: THE DISTRIBUTIVE FORMULA IS</h2>

$\text{a(b + c)} \\ \text{a(b) + a(c)} \\ \text{a(b) = ab} \\ \text{a(c) = ac} \\ \text{ \underline{ = ab + ac}}$

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3 years ago

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In the adjoining figure , APB and AQC are equilateral triangles. Prove that PC = BQ. ( Hint : <img src="https://tex.z-dn.net/?f=

just olya [345]

Answer:

See Below.

Step-by-step explanation:

Statements: Reasons:

$\displaystyle 1)\text{ } \Delta APB \text{ and } \Delta AQC \text{ are equilateral triangles}$ Given

$\displaystyle 2) \text{ } m \angle PAB = 60$ Definition of equilateral.

$3)\text{ } m \angle QAC = 60$ Definition of equilateral.

$4)\text{ } m\angle PAB = m\angle QAC$ Substitution

$5)\text{ } m\angle PAC=m\angle PAB+m\angle BAC$ Angle Addition

$\displaystyle 6)\text{ } m\angle QAB=m\angle QAC+m\angle BAC$ Angle Addition

$7)\text{ } m\angle QAB=m\angle PAB+m\angle BAC$ Substitution

$\displaystyle 8)\text{ } m\angle PAC=m\angle QAB$ Substitution

$9)\text{ } PA=BA$ Definition of equilateral

$10)\text{ } AC=AQ$ Definition of equilateral

$\displaystyle 11)\text{ } \Delta PAC \cong \Delta BAQ$ Side-Angle-Side Congruence*

$\displaystyle 12)\text{ } PC=BQ$ CPCTC

* SAS Congruence:

PA = BA

∠PAC = ∠QAB

AC = AQ

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