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3 years ago

In triangle ABC, AB measures 25 cm and AC measures 35 cm.

Mathematics

2 answers:

Natasha2012 [34]3 years ago

6 0

The answer is 10<n<60

70<p<120

Helen [10]3 years ago

4 0

10<s<60 and 70<p<120

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I need help to the attachment down below, first answer gets 5 stars and a thanks!

Gekata [30.6K]

Answer:

base = 15 units

Step-by-step explanation:

We are given area of a triangle = 52.5 sq. units

Height is given as 7 and we have to find the base.

Using formula for area of triangle:

Area of triangle = $\frac{base*height}{2}$

$52.5 = \frac{base*height}{2}$

$52.5 = \frac{base*7}{2}$

52.5 * 2 = base × 7

105 = base × 7

base = 15

3 0

3 years ago

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6. A cylindrical oatmeal canister has a diameter of 4 inches and a hight of 10 inches. The manufac-

Arlecino [84]

B. 8 inches, hope this was right and helped:)

6 0

3 years ago

Line AB contains points A(-6,1) and B(1,4).

Free_Kalibri [48]

To solve this problem you must apply the proccedure shown below:

1- You have that the equation of the line is:

$y=mx+b$

Where $m$ is the slope and $b$ is the y-intercept.

2- Based on the information given in the problem, the lines $AB$ and $CD$ are parallel, which means that both have the same slope. Therefore, you can calculate the slope of $AB$ :

$m=\frac{y2-y1}{x2-x1}$

$m=\frac{4-1}{1-(-6)}=\frac{3}{7}$

3- Use the coordinates of the point $D(7,2)$ to calculate the y-intercept:

$2=\frac{3}{7}(7)+b$

4. Solve for $b$ :

$b=2-3=-1$

5. The equation of the line $CD$ is:

$y=\frac{3}{7}x-1$

The answer is: $y=\frac{3}{7}x-1$

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3 years ago

What to know for geometry flvs module 3 DBA?

pishuonlain [190]

Essentially look at your formula sheets, Take notes on your assessment questions and you should be fine.

5 0

3 years ago

Write the following quotient in the form a+bi.<br> -7i/2-7i

Helga [31]

Answer:

$\large\boxed{\dfrac{49}{53}-\dfrac{14}{53}i}$

Step-by-step explanation:

$\text{Use}\\\\i=\sqrt{-1}\to i^2=-1\\\\(a-b)(a+b)=a^2-b^2\to(a-bi)(a+bi)=a^2+b^2\\\\\text{distributive property}\ a(b+c)=ab+ac\\---------------------\\\\\dfrac{-7i}{2-7i}=\dfrac{-7i}{2-7i}\cdot\dfrac{2+7i}{2+7i}=\dfrac{-7i(2+7i)}{2^2+7^2}=\dfrac{(-7i)(2)+(-7i)(7i)}{4+49}\\\\=\dfrac{-14i-49i^2}{53}=\dfrac{-14i-49(-1)}{53}=\dfrac{-14i+49}{53}\\\\=\dfrac{49}{53}-\dfrac{14}{53}i$

8 0

3 years ago

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