Answer:
The magnitude of the induced Emf is 
Explanation:
The width of the truck is given as 79inch but we need to convert to meter for consistency, then
The width= 79inch × 0.0254=2.0066 metres.
Now we can calculate the induced Emf using expresion below;
Then the 
Where B= magnetic field component
L= width
V= velocity
=(40*10^-6) × (42) × (2.0066)
=0.003371V
Therefore, the magnitude emf that is induced between the driver and passenger sides of the truck is 0.003371V
Subscript... shows how many atoms of an element is present in a substance
Answer:
image is vertical at distance -203.62 cm
magnification is 2.110
Explanation:
given data
n = 1.51
distance u = 96.5 cm
concave radius r1 = 24 cm
convex radius r2 = 19.1 cm
to find out
final image distance and magnification
solution
we will apply here lens formula to find focal length f
1/f = n-1 ( 1/r1 - 1/r2) .......................1
put here all value
1/f = 1.51 -1 ( -1/24 + 1/19.1)
f = 183.43
so from lens formula
1/f = 1/v + 1/u .............................2
put here all value and find v
1/183.43 = 1/v + 1/96.5
so
v = −203.62 cm
so here image is vertical at distance -203.62 cm
and
magnification are = -v /u
magnification = 203.62 / 96.5
magnification is 2.110
