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zepelin [54]
3 years ago
12

-10 = 0v a. no solution b. infinite solution

Mathematics
2 answers:
Olenka [21]3 years ago
6 0
That answer is a no solution
Wewaii [24]3 years ago
5 0

Answer:

A. no solution

Step-by-step explanation:

You cannot divide any number by 0.  It is undefined.

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What is the slope of the line through the points (4, 2) and (-16, -6)?
Harrizon [31]
Gradient = change in y /change in x so -6-2 =-8 / -16-4 = -20 so -8/-20 = 0.4 so gradient = 0.4
3 0
3 years ago
Help pleaseeeeeeeeeee
vova2212 [387]

Answer:

B & C

Step-by-step explanation:

The two binomials are equal to zero to find the roots.

Hope this helps

6 0
2 years ago
Tommy and his friend went to go buy pie at Delicious Orchards. After paying seven dollars for the pie, Tommy
wlad13 [49]

Answer:

$102

Step-by-step explanation:

if Tommy spent 7 dollars on pie, that means he had more money than that amount before.

So before he spent 7 dollars, he had those 7 dollars.

Add 7 with 95

95 + 7 = 102

5 0
3 years ago
What is the solution to the equation 6t = 114
Tpy6a [65]
Divide the 114 by 6t to get an anwer

7 0
3 years ago
Read 2 more answers
How many elements does A contains if it has 64 subsets​
Amanda [17]
<h3>Answer:  6</h3>

===========================================================

Explanation:

Rule: If a set has n elements in it, then it will have 2^n subsets.

For example, there are n = 3 elements in the set {a,b,c}. This means there are 2^n = 2^3 = 8 subsets. The eight subsets are listed below.

  1. {a,b,c} .... any set is a subset of itself
  2. {a,b}
  3. {a,c}
  4. {b,c}
  5. {a}
  6. {b}
  7. {c}
  8. { } ..... the empty set

Subsets 2 through 4 are subsets with exactly 2 elements.  Subsets 5 through 7 are singletons (aka sets with 1 element). The last subset is the empty set which is a subset of any set. You could use the special symbol \varnothing to indicate the empty set.

For more information, check out concepts relating to the power set.

-------------------

The problem is asking what value of n will make 2^n = 64 true.

You could guess-and-check your way to see that 2^n = 64 has the solution n = 6.

Another approach is to follow these steps.

2^n = 64\\\\2^n = 2^6\\\\n = 6

Which is fairly trivial.

Or you can use logarithms to solve for the exponent.

2^n = 64\\\\\text{Log}\left(2^n\right)=\text{Log}\left(64\right)\\\\n*\text{Log}\left(2\right)=\text{Log}\left(64\right)\\\\n=\frac{\text{Log}\left(64\right)}{\text{Log}\left(2\right)}\\\\n\approx\frac{1.80617997398389} {0.30102999566399} \ \text{ ... using base 10 logs}\\\\n\approx5.99999999999983\\\\

Due to rounding error, we don't land exactly on 6 even though we should.

5 0
2 years ago
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