Given BD and AC is a diameter of the circle:
We need to find the following:
1. measure of the arc BA
So,
the measure of the minor arc BA = 44
The measure of the major arc BA = 360 - 44 = 316
2. the measure of the arc ACB = 360 - 44 = 316
3. The arc BCD is a semicircle of the circle
So, the measure of the arc BCD = 180
Simplified as a decimal could be 0.02
Answer:
4.03cm
Step-by-step explanation:
Note that the diameter of the circumscribed circle to the right triangle is the hypotenuse of the triangle.
To get the diameter, we will use the pythagoras theorem as shown;
d² = 7² + 4²
d² = 49 + 16
d² = 65
d = √65
d = 8.0622577
Since radius = d/2
radius = 8.0622577/2
radius = 4.0311288
Hence the radius of the circumscribed circle to the nearest hundredth is 4.03cm
