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tiny-mole [99]
2 years ago
7

3x + 2 y = 8 5x + 2 y = 12 What is the solution of the system of equations shown above?

Mathematics
1 answer:
Arisa [49]2 years ago
5 0

Answer:

x = -3

Step-by-step explanation:

First solve it:

Subtract the x's from both sides

2y = -3x +8

2y = -5x +2

Divide by two

y= -1.5x + 4

y = -2.5x +1

set them equal to each other:

-1.5x +4 = -2.5x +1

Add 2.5 x to both sides

1x +4 = 1

x +4 = 1

subtract 4 from both sides

x = -3

You might be interested in
Three fifths of one sixths evaulate expression
sukhopar [10]

3/5 of 1/6 is written as

3/5 x 1/6

Multiply both the numerator and denominators together:

3x1 / 5*6 = 3/30, reduces to 1/10.


The answer is 1/10.

3 0
3 years ago
Read 2 more answers
An equation is shown below: 3(2x − 7) = 9
Katen [24]

Answer:

1 solution

Step-by-step explanation:

3(2x-7)=9

dustribute: (3)(2)+(3)(-7x)=9

6+-21x=9

subtract 6 from both sides: -21x=3

Divide both sides by -21: x=-1/7

so your 1 solution is x = - 1/7

3 0
2 years ago
5. Katie makes and sells scarves. Her monthly profit is given by P(s) = -s2 + 25s - 100, where "s" is the selling price. For wha
Marat540 [252]

Answer: s > 5

Step-by-step explanation:

-s² + 25s - 100 > 0

Coefficient of s² is -1, multiply the equation through by -1.

-1 × (-s² + 25s - 100)

s² — 25s + 100

ax² + bx + c

Then you get the factors x and y that gives x + y = b and xy = c

b = -25 and c = 100, x = -20 and y = -5

-20 × -5 = 100 and -20 + -5 = -25

Then

s² — 20s — 5s + 100 > 0

Factorising,

s (s — 20) — 5(s — 20) > 0

(s — 5)(s — 20) > 0

(s — 5) > 0 and (s — 20) > 0

s>5 and s>20

s > 5

Hope this Helps?

4 0
3 years ago
What is the solution to the equation x – 12 = –3?
natima [27]
My answer is C
because
x-12=-3
x=-3+12
x=9
6 0
3 years ago
What is the remainder of the quantity 5 x cubed plus 7 x plus 5 end quantity divided by the quantity x plus 2 end quantity? Show
jarptica [38.1K]

The remainder of the polynomial equation is -49

<h3>What is a remainder of a polynomial equation?</h3>

The remainder of a quantity in an algebraic expression of a polynomial equation is the remaining amount of the quantity left and can not be divisible by the divisor.

From the given information, we are to find the remainder of the given algebraic equation:

\mathbf{= \dfrac{5x^3+7x+5}{x+2} }

Using the long division method, we have:

\mathbf{= \dfrac{5x^3+7x+5}{x+2} } \implies \mathbf{5x^2 + \dfrac{-10x^2+7x+5}{x+2}}

Divide by \mathbf{ \dfrac{-10x^2+7x+5}{x+2}}, we have:

\mathbf{= 5x^2- 10x+ \dfrac{27x+5}{x+2}}

Divide by \mathbf{\dfrac{27x+5}{x+2}}, we have:

\mathbf{= 5x^2- 10x+ 27 +\dfrac{-49}{x+2}}

Learn more about finding the remainder of a polynomial equation here:

brainly.com/question/24978997

#SPJ1

4 0
1 year ago
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