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Stolb23 [73]
3 years ago
9

PLEASE HELP ME please

Mathematics
1 answer:
Lena [83]3 years ago
7 0

Answer:

(-1, 1/10) and (-2, 1/100)

I can't really explain because I just put it into my graphing calculator and clicked the trace button to find the y value at certain x values. A good website to do that on is Desmos

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Pls help with math ASAP
Natasha_Volkova [10]
125.6


Area of a circle = πr^2
Area of circle 1 = 3.14 × 11 × 11
=379.94cm^2
Area of circle 2= 3.14 × 9 ×9
=254.64cm^2
Area of a shaded region
=379.94cm^2 - 254.64cm^2
=125.60cm^2

3 0
3 years ago
Please help ASAP ;)
Taya2010 [7]

Answer:     use PEMDAS

Step-by-step explanation:  

8 0
3 years ago
Uhm help please no links -^-
devlian [24]

Answer:

<u>x = 58</u>

Step-by-step explanation:

180 - 148 = 32

32 + 90 + x = 180

122 + x = 180

180 - 122 = x

x = 58

Have a nice day!

6 0
3 years ago
Read 2 more answers
I don’t know how to do this problem and need help getting answer?
3241004551 [841]

Hi!!! So to do this problem, you need to find the mean values for each sample. I will walk you through finding the mean of sample 1: first you want to add all of the values for sample 1, which are 4,5,2,4 and 3. Once you add those values you get 18. Then you must divide that 18 by the number of terms you added. The numbers you added were 4,5,2,4 and 3 like I said earlier which is 5 numbers. You divide 18 by 5 to get your mean, which is 3.6

Answer: (B) Sample 2

sample 1 mean = 3.6

sample 2 mean = 4.2

sample 3 mean = 3.8

sample 4 mean = 4

8 0
3 years ago
2. Given the equation of a circle in standard form, identify the center, radius, and graph the circle.
Varvara68 [4.7K]

Answer:

Center: ( -1 , 2 )

Radius: 6

Step-by-step explanation:

The equation for a circle is given as follow:

(x-h)^{2} +(y-k)^{2} =r^{2}

Where,

the Center is: ( h , k ) (note that the signs of the number are different)

and the radius is: r

So if we compare the original circle equation to the equation in the question we can see that:

(x+1)^{2} +(y-2)^{2} =36

the Center is: (-1,2)

and the radius is: \sqrt{36} = 6

2. To draw the graph find points that lay on the circle, it's better to take the values of x and y from the Center:

first sub y=2 in the equation to find the values for x:

(x+1)^{2} +(y-2)^{2} =36

(x+1)^{2} +(2-2)^{2} =36

(x+1)^{2} +(0)^{2} =36

(x+1)^{2}  =36

x+1 =±\sqrt{36}

x=6-1    AND    x=-6-1

x=5          AND    x=-7

  • The points are A(5,2)  and  B(-7,2)

second sub x= -1 in the equation to find the values for y:

(x+1)^{2} +(y-2)^{2} =36

(-1+1)^{2} +(y-2)^{2} =36

(0)^{2} +(y-2)^{2} =36

(y-2)^{2} =36

y-2=±\sqrt{36}

y=6+2    AND    y=-6+2

y=8          AND    y=-4

  • The points are D(-1,8)  and  E(-1,-4)      

After finding the points write them in the graph and match them together to get the like the circle in the picture below:

8 0
3 years ago
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