Determine the value of y.

3x – 4y = 10<br> 2x – 4y = 6<br> what is the value of y?

Lorico [155]

3x- 4y=10

10÷1=10

Therefore y is equal to 10

3 0

2 years ago

which detail best describes this map? shows isolines and isobars shows types of precipitation was created for newspapers is prob

uysha [10]

Answer:

Its A

Explanation:

got it right

5 0

2 years ago

Factor the expression into an equivalent form 12y^2-75.

elena-14-01-66 [18.8K]

Hello oddworld7836!

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

Factor the expression into an equivalent form 12y² - 75.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

$12 y ^ { 2 } - 75$

By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.

$12 y ^ { 2 } - 75 \\ = 3\left(4y^{2}-25\right)$

Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,

a² = 4, a = 2 (√a² = ✓4 = 2)
b² = 25, b = 5 (√b² = ✓25 = 5)

So, the (4y² + 25) becomes...

$(4 {y}^{2} - 25) \\ = \left(2y-5\right)\left(2y+5\right)$

Now, bring the 3 (common factor) & rewrite the complete expression.

$12 y ^ { 2 } - 75 \\ = \boxed{ \boxed{ \bf \: 3\left(2y-5\right)\left(2y+5\right) }}$

We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.

__________________

Hope it'll help you!

ℓu¢αzz ッ

8 0

2 years ago

Zachary has been trying to work on an essay for almost three hours, be he can't seem to focus for more than 15 or 20 minutes at

ludmilkaskok [199]

well first he would have to work intervals at a time for example 15 min study intervals then snack break but only brain foods to help his memory then repeat the proceed until desired time

plz mark brainliest

3 0

3 years ago

The professor informs the class that there will be a test next week. what is the probability that a randomly selected student st

marusya05 [52]

The probability that students who were randomly selected studied for the test, if they pass it with a B or higher grade is: D. 0.80.

<h3>How to calculate the probability?</h3>

In this exercise, you're required to determine the probability that students who were randomly selected studied for the test, if they pass it with a B or higher grade. Thus, we would apply Bayes's theorem.

Let S represent studied for.

Let B represent a score of B or higher grade

Therefore, we need to find P(S|B):

$S|B = \frac{B|S \times S}{B|S \times S\; +\; B|S' \times S'} \\\\S|B = \frac{0.55 \times 0.6}{0.55 \times 0.6 \;+ \;0.2 \times 0.4}\\\\S|B =\frac{0.33}{0.33 + 0.08} \\\\S|B =\frac{0.33}{0.41}$

S|B = 0.80.

Read more on probability here: brainly.com/question/25870256

#SPJ1

<u>Complete Question:</u>

At the beginning of the semester, a professor tells students that if they study for the tests, then there is a 55% chance they will get a B or higher on the tests. If they do not study, there is a 20% chance that they will get a B or higher on the tests. The professor knows from prior surveys that 60% of students study for the tests. The probabilities are displayed in the tree diagram.

5 0

1 year ago