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zalisa [80]
3 years ago
5

Solve each equation.

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
4 0
Just use mathpapa.com it’ll give you all them answers
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I gave my brother 1/5 of my candy, 1/4 to my friend and had 11 pieces left over. How many pieces did I give my brother?
AnnyKZ [126]

x = total number of candies

\bf \stackrel{\textit{my brother}}{\cfrac{1}{5}x}+\stackrel{\textit{my friend}}{\cfrac{1}{4}x}+11~~=~~\stackrel{\textit{total}}{x} \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{20}}{20\left( \cfrac{x}{5}+\cfrac{x}{4}+11 \right)=20(x)}\implies 4x+5x+220=20x\implies 9x+220=20x \\\\\\ 220=11x\implies \cfrac{220}{11}=x\implies 20=x~\hspace{10em}\stackrel{\textit{to my brother}}{\cfrac{20}{5}\implies 4}

4 0
3 years ago
Suppose I pick a jelly bean at random from a box containing two red and ten blue ones. I record the color and put the jelly bean
Lubov Fominskaja [6]

Answer:

The probability of getting a red jelly bean both of the times is 0.028.

Step-by-step explanation:

First we have that in the box are 12 jelly beans having 2 red and 10 blue. The probability of getting one of the red jelly beans are the sum of the probability of the 2 red jelly beans, that is:

ProbabilityRed=\frac{1}{12} +\frac{1}{12}=\frac{2}{12}

Now we can calculate the probability of getting the red jelly bean twice, this will be the product of the probability of getting each one, is the same probability for the second chance because we are getting the jelly bean back in the box, this is:

ProbabilityBothRed=\frac{2}{12} *\frac{2}{12}=\frac{4}{144}  =\frac{1}{36} =0.028

Now we have that the probability of getting a red jelly bean both of the times is 0.028.

6 0
4 years ago
Otto spent 3/4 of the money he had saved on a new video game. If the video game cost $48, how much money did he have before he b
quester [9]

Answer: $64

Step-by-step explanation:

Given: The part of money he spent =3/4

Let the total money Otto has be 'x'.

Then according to the question, we have

\frac{3}{4}x=48

Multiply 4 on both the sides, we get

3x=48\times4

Divide 3 on both the sides, we get

x=\frac{48\times4}{3}\\\\\Rightarrow\ x=64

Hence, the money he had  before he bought the game = $64

5 0
3 years ago
Read 2 more answers
3b^2-4b+1=0 solve each equation with the quadratic formula
hjlf
First multiply 3 and the 1
Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve

7 0
4 years ago
1) y = |x+4| - 1<br><br><br><br> This needs to be graphed, please help!
otez555 [7]

Answer:

Attachment

Step-by-step explanation:

x = 0

y = | 0 + 4 | - 1

y = 4 - 1

y = 3

y = 0

0 = | x + 4 | - 1

1 = | x + 4 |

x + 4 = 1 => x₁ = 1 - 4 => x₁ =  - 3

x + 4 = - 1 => x₂ = - 1 - 4 => x₂ = - 5

7 0
4 years ago
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