Answer:
The probability of getting a red jelly bean both of the times is 0.028.
Step-by-step explanation:
First we have that in the box are 12 jelly beans having 2 red and 10 blue. The probability of getting one of the red jelly beans are the sum of the probability of the 2 red jelly beans, that is:

Now we can calculate the probability of getting the red jelly bean twice, this will be the product of the probability of getting each one, is the same probability for the second chance because we are getting the jelly bean back in the box, this is:

Now we have that the probability of getting a red jelly bean both of the times is 0.028.
Answer: $64
Step-by-step explanation:
Given: The part of money he spent =3/4
Let the total money Otto has be 'x'.
Then according to the question, we have

Multiply 4 on both the sides, we get

Divide 3 on both the sides, we get

Hence, the money he had before he bought the game = $64
First multiply 3 and the 1
Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve
Answer:
Attachment
Step-by-step explanation:
x = 0
y = | 0 + 4 | - 1
y = 4 - 1
y = 3
y = 0
0 = | x + 4 | - 1
1 = | x + 4 |
x + 4 = 1 => x₁ = 1 - 4 => x₁ = - 3
x + 4 = - 1 => x₂ = - 1 - 4 => x₂ = - 5