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3 years ago

Is the graph below linear function or non- linear plxxx helppp

Mathematics

1 answer:

Eduardwww [97]3 years ago

8 0

Answer:

It is non linear

Step-by-step explanation:

Linear means that it goes at a constant rate (aka a straight line)

This graph does not have a straight line so it is non-linear

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Which is an equivalent form of the expression 1800(1.2)^-t

ololo11 [35]

Answer:

1800(5/6)^t

Step-by-step explanation:

I don't see any answer choices, but this would be another form if it is listed. The negative exponent means that you get the reciprocal of the fraction (in this case 1.2). This turns 1.2 into (1/1.2), which is equivalent to 5/6.

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1 year ago

Find the length of UV.

katovenus [111]

7x-8 (2) = 12x+8
14x-16 = 12x+8
-12x -12x
2x-16 = 8
+16 +16
2x = 24

÷2 ÷2
x= 12

UV= 7x-8
UV= 7(12)-8
UV= 84-8
UV= 76

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2 years ago

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nikklg [1K]

Answer: A y=4x^2+1

Step-by-step explanation:According to slope A is the answer

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3 years ago

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Which is not a proportion???

frez [133]

The answer is C. C is not a proportion.

Hope this helps!

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2 years ago

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Find gradient xe^y + 4 ln y = x² at (1, 1)

cricket20 [7]

$xe^y+4\ln y=x^2$

Differentiate both sides with respect to x, assuming y = y(x).

$\dfrac{\mathrm d(xe^y+4\ln y)}{\mathrm dx}=\dfrac{\mathrm d(x^2)}{\mathrm dx}$

$\dfrac{\mathrm d(xe^y)}{\mathrm dx}+\dfrac{\mathrm d(4\ln y)}{\mathrm dx}=2x$

$\dfrac{\mathrm d(x)}{\mathrm dx}e^y+x\dfrac{\mathrm d(e^y)}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

$e^y+xe^y\dfrac{\mathrm dy}{\mathrm dx}+\dfrac4y\dfrac{\mathrm dy}{\mathrm dx}=2x$

Solve for dy/dx :

$e^y+\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x$

$\left(xe^y+\dfrac4y\right)\dfrac{\mathrm dy}{\mathrm dx}=2x-e^y$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2x-e^y}{xe^y+\frac4y}$

If y ≠ 0, we can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2xy-ye^y}{xye^y+4}$

At the point (1, 1), the derivative is

$\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=1,y=1}=\boxed{\dfrac{2-e}{e+4}}$

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3 years ago

Is the graph below linear function or non- linear plxxx helppp​

Is the graph below linear function or non- linear plxxx helppp