Answer:
Mike is not right
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared
Let
z----> the scale factor
x----> surface area of the enlarged rectangular prism
y-----> surface area of the original rectangular prism
so
In this problem we have
substitute
so
The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism
therefore
Mike is not right
<em>Verify with an example</em>
we have a rectangular prism
The surface area of the prism is equal to
substitute the values
If he doubles each dimension of any rectangular prism
then
the new dimensions will be
The new surface area will be
therefore
The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism
Answer:
Perimeter = 8x
Step-by-step explanation:
If I can see correctly, the area of the squares are x². Area is just s², so we can find one side by finding the square root of x², which is x. Now that we know that x is one side, we can count the amount of sides and multiply that number by x.
There are 8 sides, so the answer is P = 8x
What the two or more numbers or amounts? Something needs to be compared
Answer:
center point: (-4, 2)
radius: 8 units
Step-by-step explanation:
To find the radius of a figure in a coordinate plane, you have to do x-y where x is the starting point and y is the ending point. so in this case:
-4-(-12)
= -4+12
= 8
PART 1.
Going westward:
Distance: 2400 miles
Rate (this is speed): (450-wind_speed) mph
Time: distance / speed = 2400 / (450-wind speed)
Going eastward:
Distance: 2400 miles
Rate (this is speed): (450+wind_speed) mph
Time: distance / speed = 2400 / (450+wind speed)
PART 2
Formula for speed:
speed = distance / time
Now we solve this for time:
time = distance / speed
11h = 2400 / (450+-wind_speed)
+- sign is put because in one case wind increases speed of plane and in other case it decreases speed.
PART 3
To solve for wind_speed we start by rearranging formula so that we have wind_speed on left side:
(450+-wind_speed) = 2400 / 11
(450+-wind_speed) = 218mph
To fly this distance in 11h speed of plane must be 218mph.
The only way to get this solution is if we substract wind speed:
450-wind_speed = 218
wind_speed = 450-218 = 232mph
