Answer:
a) Sample size = 822
b) Margin of error = 0.03407
Step-by-step explanation:
We are given the following in the question:
p = 74% = 0.74
a) Sample size is required to obtain margin of error of 0.03
Formula:


Putting values, we get,

Thus, the sample size must be approximately 822 to obtain a 95% confidence interval with an approximate margin of error of 0.03
b) Margin of error for the 95% confidence interval
p = 54% = 0.54
Formula:


Putting values, we get,

The margin of error now will be 0.03407.
12x - 13 = -6x + 17
12x+6x=17+13
18x=30
X= 30÷18
X= 1.66667
This makes no sense, not enough information is provided.
You will save $4,226.16 because $5,000 + 24 x $551.09 = $18,226.16
To get how much is saved take the higher number and subtract the lower one,
$18,226.16 - $14,000 = $4,226.16