Answer:
C
Step-by-step explanation:
![y^{-\frac{4}{3}} = \frac{1}{y}^{\frac{4}{3}} = \sqrt[3]{\frac{1}{y}} = \frac{1}{\sqrt[3]{y^4}}](https://tex.z-dn.net/?f=y%5E%7B-%5Cfrac%7B4%7D%7B3%7D%7D%20%3D%20%5Cfrac%7B1%7D%7By%7D%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7By%7D%7D%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7By%5E4%7D%7D)
I hope I've helped you.
Answer: 14 turkeys and a cat
Step-by-step explanation: Getting 32 feet from 15 heads shows that an animal has more than 2 feet. If the 15 heads all belonged to turkeys, we'd have 30 feet (which is 2 short of what was observed). Reducing the number of turkey by 1 and adding a cat balances the number of observed feet. That is, 14 turkeys (with a total of 28 feet) and a cat (with 4 feet). Adding, we have 28+4=32
3q+21c
q=7
If this helped please give stars and a thanks ^.^ much appreciated!
Answer:
The probability that a student is taking math or computer science is 0.37
Step-by-step explanation:
The probability that a student is taking math =P(M)=33% =0.33
The probability that a student is taking computer science =P(C)= 62%=0.62
The probability that a student is taking math and computer science =P(M∩C)= 58%=0.58
So, the probability that a student is taking math or computer science i.e.P(M∪C)
So, Formula:P(A∪B)=P(A)+P(B)-P(A∩B)
P(M∪C)=P(M)+P(C)-P(M∩C)
P(M∪C)=0.33+0.62-0.58
P(M∪C)=0.37
Hence the probability that a student is taking math or computer science is 0.37
