Answer:
0,006 I assume.
Step-by-step explanation:
Let's first denote:
F - a favorable response
F' - an unfavorable response
S - successful
We know that:

So, from the conditional probability, we can calculate:

Answer E.
Answer:
(a)
(b) 
Step-by-step explanation:
It is given that
.
(a)
(b)
![[\because \sin x=\dfrac{1}{\csc x}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csin%20x%3D%5Cdfrac%7B1%7D%7B%5Ccsc%20x%7D%5D)

Therefore,
.
Answer: 72.4
Step-by-step explanation:
Fraction of six-grade students that have at least one pet = 2/5
Number of sixth graders at Brunswick Elementary school = 181
The number of sixth graders that own own pets will be:
= 2/5 × 181
= 72.4