All you need to do is convert all equations into standard form by using the distributive property on each equation.
Answer:
Step-by-step explanation:
Below is an attachment containing the solution to the question.
4p^3(4p/1) is the answer (slash and divided are the same thing in case there's confussions)
Rectangle diagonals are equal.
2(5a+1) = 2(a+1)
10a + 2 = 2a + 2
10a -2a = 2 - 2
8a = 0
⇒ a = 0
AC = 2(5a+1) = 2(5 × 0 +1)= 2(0 + 1) = 2 × 1 = 2 <span>
</span>BD = 2(a+1) = 2(0 + 1) = 2 <span>× 1 = 2
</span>
Ansver: AC = BD = 2
Answer:
The smallest of the two consecutive integers is 10 or less.
Step-by-step explanation:
Let x represent the smallest of the even integers in the sequence.
Then the sum of two consecutive even integers is ...
x + (x +2) = 2x +2
And half the sum of the next two consecutive even integers is ...
(1/2)((x +4) + (x +6)) = x + 5
The relationship between these values is ...
2x +2 ≤ 7 + (x +5)
Subtracting x+2 gives ...
x ≤ 10
The least of the two consecutive even integers is at most 10.
