Question

Help me with this question, please!

Answer 1

Answer:

3,432 m²

Step-by-step explanation:

The amount of aluminum in square meters needed to make the mailboxes = 1863(surface area of each mailbox)

Surface area of each mail box = ½(surface area of cylinder) + (Surface area of rectangular prism/box - area of the surface of the box that joins the half-cylinder)

✔️Surface area of ½-cylinder = ½[2πr(h + r)]

r = ½(0.4) = 0.2 m

h = 0.6 m

π = 3.14

Surface area of ½-cylinder = ½[2*3.14*0.2(0.6 + 0.2]

= 0.628(0.8)

Surface area of ½-cylinder = 0.5024 m²

✔️Surface area of the rectangular box/prism = 2(LW + LH + WH)

L = 0.6 m

W = 0.4 m

H = 0.55 m

Surface area = 2(0.6*0.4 + 0.6*0.55 + 0.4*0.55)

Surface area of rectangular box = 1.58 m²

✔️Area of the surface joining the half cylinder and the box = L*W = 0.6*0.4 = 0.24 m²

✅Surface area of 1 mailbox = (0.5024) + (1.58 - 0.24)

= 0.5024 + 1.34

= 1.8424

Amount of aluminum needed to make 1863 mailboxes = 1863 × 1.8424 = 3,432.3912

= 3,432 m²