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Molodets [167]
3 years ago
8

How do I find the perimeter of a triangle with sides 3ft 8in., 2ft 10in., and 4 ft?

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
4 0
Formula for triangle perimeter is: a + b + c. In this scenario we have:

a = 3 feet 8 inches
b = 2 feet 10 inches
c = 4 feet

a + b + c =
= 3 ft + 8 in + 2 ft + 10 in + 4 ft =
= 9 ft + 18 in

We know that 1 foot is 12 inches, so we can simplify the result to this form:

10 ft + 6 in

or:

<u>10.5 feet</u>
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14-12x+39x-18x=256-60x-657x​
emmasim [6.3K]

Answer:

\boxed{\bold{x=\frac{1}{3}}}

Step-by-step explanation:

Combine Similar Elements: \bold{-12x+39x-18x=9x}

\bold{14+9x=256-60x-657x}

Combine Similar Elements: \bold{-60x-657x=-717x}

\bold{14+9x=256-717x}

Subtract 14 From Both Sides

\bold{14+9x-14=256-717x-14}

Simplify

\bold{9x=-717x+242}

Add \bold{717x} To Both Sides

\bold{9x+717x=-717x+242+717x}

Simplify

\bold{726x=242}

Divide Both Sides By \bold{726}

\bold{\frac{726x}{726}=\frac{242}{726}}

Simplify

\bold{x=\frac{1}{3}}

4 0
3 years ago
what is the area of a regular pentagon with sides of length 13 and an apothem of length 8.95, in square units
Assoli18 [71]
The area is 290.760680699535.
3 0
3 years ago
The attendance office creates a bar graph to display the number of students tardy throughout the month. What is the range of the
aliina [53]

Answer:

60

Step-by-step explanation:

To find the range you subtract the highest and lowest value

The highest value on this graph is 105 from the month of May and the lowest value is 45 from the month of March.

When you do 105-45 you get 60 which is the range

5 0
3 years ago
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

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2 years ago
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prisoha [69]
Multiply 5 by 4.22 because 5 cups of water is 4.22 liters
7 0
2 years ago
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