How do I find the perimeter of a triangle with sides 3ft 8in., 2ft 10in., and 4 ft?
1 answer:
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Answer:
see explanation
Step-by-step explanation:
This is a difference of squares and factors in general as
a² - b² = (a - b)(a + b)
16 = ( 4
)² ⇒ a = 4
1 = 1² ⇒ b = 1
Hence
16 - 1
= (4 )² - 1²
= (4 - 1)(4
+ 1)
4 - 1 ← is also a difference of squares and factors as
(2x² - 1)(2x² + 1)
Thus
16 - 1
= (2x² - 1)(2x² + 1)(4 + 1 )
The answer is C. You can make a rectangle by putting the diagonals through the center anywhere, but if you want a square, you have to put the two diagonals perpendicular to each other and join their ends. See the diagram.
