A single die is rolled twice. the set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
Maksim231197 [3]
<span>We need to find the rolls whose sum is greater than 10. By looking at the outcomes, we see that (5,6), (6,5), and (6,6) all have a sum greater than 10. Therefore, there are 3 chances to get a sum greater than 10. Since there are 36 chances overall, the probability of rolling greater than 10 are 3/36 = 1/12.</span>
Answer:...,,,.
Step-by-step explanation:.....,l,,
Answer:
0.87 > 0.17
3.97 < 6.63
8.04 < 8.9
Is that what ur looking for?
Step-by-step explanation:
1. v=0
2. No solution
3. m=0
4. No solution
5. p= -7
6. x=5
7. -12 = - 12
8. x=5
9. 3=3
10. -32= -32
11. x=0
12. No solution
I'm sorry if anything is wrong.
