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3 years ago

Which notation is equivalent to the inequality -3 < x ≤ 7?

1 answer:

6 0

The notation that is equivalent to -3 < x ≤ 7 is (2) (-3, 7].

|---|---|---|---|---|---|---(---|---|---|---|---|---|---|---|---|---]---|---|---|
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10

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What are the length and width of your scale drawing?

SpyIntel [72]

Answer:

i don't see anything attached

Step-by-step explanation:

by the way can i have brainliest

3 0

3 years ago

Value of x is in solution set of 8x-6>12+2x

quester [9]

Answer:

x>3

Step-by-step explanation:

8x-6>12+2x

Subtract 2x from each side

8x-2x-6>12+2x-2x

6x -6 > 12

Add 6 to each side

6x-6 +6 > 12+6

6x> 18

Divide each side by 6

6x/6 >18/6

x>3

8 0

4 years ago

Mary weighs n kg while her sister weighs 15 kg less. How many times is Mary heavier than her sister?

kari74 [83]

Answer:

Mary is $\frac{n}{n-15}$ times heavier than her sister

Step-by-step explanation:

Mary's Weight = n

Sister's Weight = n - 15

To find how many times mary is heavier, we need to multiply "that many time" [let it be x] with sister's weight to get Mary's weight.

<u>e.g. </u>If someone weighs 100 and another person 50, 50 * 2 = 100, thus, 100 kg person is 2 times heaving. We do same for this:

(n - 15) * x = n

x = n/(n - 15)

3 0

3 years ago

Read 2 more answers

If RX=4 and XS=9, then XT=<br> And how do you get it?

konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

$RS^2=RT^2+TS^2$

we have

$RS=RX+XS=4+9=13\ units$ ---> by segment addition postulate

substitute

$RT^2+TS^2=169$ ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

$RT^2=RX^2+XT^2$

we have

$RX=4\ units$

substitute

$RT^2=4^2+XT^2$

$RT^2=16+XT^2$

$XT^2=RT^2-16$ ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

$TS^2=XS^2+XT^2$

we have

$XS=9\ units$

substitute

$TS^2=9^2+XT^2$

$TS^2=81+XT^2$

$XT^2=TS^2-81$ ----> equation C

step 4

equate equation B and equation C

$TS^2-81=RT^2-16$

$TS^2-RT^2=81-16$

$TS^2-RT^2=65$ ----> equation D

step 5

Solve the system

$RT^2+TS^2=169$ ----> equation A

$TS^2-RT^2=65$ ----> equation D

Solve by elimination

Adds equation A and equation D

$RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117$

Find the value of RT^2

$RT^2+117=169\\RT^2=52$

step 6

Find the value of XT

equation C

$XT^2=117-81\\XT^2=36\\XT=6\ units$

7 0

3 years ago

Is it that true ⅖-¾=¼+2/5

harkovskaia [24]

No, 2/5-3/4 is -7/20 and 1/4+2/5 is 13/20 they do not equal the same the so the answer is no because it’s not true

6 0

3 years ago