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2 years ago

14

The population of New York City is 23,945. Eastdale has a population of 12,774 What is the total population of the two communiti

es
A.35,719
B. 36,619
C. 36,719
D. 37,619

1 answer:

serious [3.7K]2 years ago

3 0

No.d
37,619

I hope that this helps you and please mark me as the brainliest.

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What is 5 to the square root of 1/2?

Pepsi [2]

Answer:

the answer is 2.5 hope it helps

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3 years ago

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A triangular lot has sides of 215m, 185m, and 125m. Find the measures of the angles at its corners

Vlada [557]

Answer:

The measures of the angles at its corners are $59.1\°,35.4\°,85.5\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle A

Applying the law of cosines

$185^{2}= 215^{2}+125^{2}-2(215)(125)cos(A)$

$2(215)(125)cos(A)= 215^{2}+125^{2}-185^{2}$

$cos(A)= [215^{2}+125^{2}-185^{2}]/(2(215)(125))$ $cos(A)=0.513953$

$A=arccos(0.513953)=59.1\°$

step 2

Find the measure of angle B

Applying the law of cosines

$125^{2}= 215^{2}+185^{2}-2(215)(185)cos(B)$

$2(215)(185)cos(B)= 215^{2}+185^{2}-125^{2}$

$cos(B)= [215^{2}+185^{2}-125^{2}]/(2(215)(185))$ $cos(B)=0.81489$

$B=arccos(0.81489)=35.4\°$

step 3

Find the measure of angle C

Applying the law of cosines

$215^{2}= 125^{2}+185^{2}-2(125)(185)cos(C)$

$2(125)(185)cos(C)= 125^{2}+185^{2}-215^{2}$

$cos(C)= [125^{2}+185^{2}-215^{2}]/(2(125)(185))$ $cos(C)=0.0784$

$C=arccos(0.0784)=85.5\°$

3 0

3 years ago

What are the zeros of f(x) = x2 - x - 20?

sattari [20]

Answer:

(-4,0) and (5,0)

Step-by-step explanation:

Factor.

f(x) = x^2 -x - 20

Factors of -20 that when are added they equal -1

-5 and 4

(x-5) (x+4)

x=5 and x=-4

5 0

3 years ago

More help is appreciated:))

Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with P (5, -1)

(5, -1) ⇾ ( 5 + 3, -1 + 6)

(5, -1) ⇾ ( 8, 5 )

P $^{1}$ = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

(0, 8) ⇾ ( 3, 14 )

Q $^{1}$ = (3, 14)

And last but not least, the point R, (7, 5)

(7, 5) ⇾ (7 + 3, 5 + 6)

(7, 5) ⇾ ( 10, 11 )

R $^{1}$ = (10, 11)

Therefore, P $^{1}$ = (8, 5), Q $^{1}$ = (3, 14), R $^{1}$ = (10, 11) is your answer. This is the 4th option or D.

Hope this for you to understand this a bit more! =D

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3 years ago

The expression cos(A-B) - cos(A+B) is equal to

olchik [2.2K]

Cos (A-B) - cos (A+B)
= (cosAcosB +sinAsinB) - (cosAcosB - sinAsinB)
=2sinAsinB

Ans: 4

6 0

3 years ago

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