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3 years ago

Anybody know this question

Mathematics

1 answer:

Dmitrij [34]3 years ago

8 0

<h3>Answers :-</h3>

sinB = 12/13
cosB = 5/13
tanB = 12/5

Here as by the given information ,

♦ sinA = Opposite/Hypotenuse

♦ cosA = Adjacent/Hypotenuse

♦ TanA = Opposite/adjacent

So here we need to find the same for angle B so we need to use the same formulas for angle B also .

→ sinB = Opposite/Hypotenuse = 12/13

→ cosB = Adjacent/Hypotenuse = 5/13

→ tanB = Opposite/Adjacent = 12/5

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