Chris wanted to know how likely he is to win at his favorite carnival game. He conducted 50 tests and won 15 times. What is the
1 answer:
You might be interested in
Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player =
The probability that athlete is a basketball player =
The probability that athlete is both basket ball player and football player =
We have to find the probability that an athlete chosen is either a football player or a basketball player .
Now we know that;
Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.