Answer:
∠RQS = 156
Step-by-step explanation:
m∠TQS = 24
∠TQS and ∠RQS are linear pair. Linear pair are two adjacent angles and their sum is 180
∠TQS + ∠RQS = 180
24 + ∠RQS = 180
∠RQS = 180 - 24
∠RQS = 156
-12=2k means k is -6
-w^2 =-81 so w =9
2f=-14 so f=-7
Answer:
The answer is
<h2>
![\sqrt{29} \: \: \: or \: \: \:5.38 \: \: \: units](https://tex.z-dn.net/?f=%5Csqrt%7B29%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20%20%5C%3A5.38%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20units)
</h2>
Step-by-step explanation:
The length of the segment connecting two points can be found by using the formula
![d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\](https://tex.z-dn.net/?f=d%20%3D%20%20%5Csqrt%7B%20%28%7Bx1%20-%20x2%7D%29%5E%7B2%7D%20%2B%20%20%28%7By1%20-%20y2%7D%29%5E%7B2%7D%20%20%7D%20%20%5C%5C%20)
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
A(1,3) and B(6,5)
The length is
![|AB| = \sqrt{ ({1 - 6})^{2} + ({3 - 5})^{2} } \\ = \sqrt{ ({ - 5})^{2} + ( { - 2})^{2} } \\ = \sqrt{25 + 4} \\ = \sqrt{29}](https://tex.z-dn.net/?f=%20%7CAB%7C%20%20%3D%20%20%5Csqrt%7B%20%28%7B1%20-%206%7D%29%5E%7B2%7D%20%2B%20%20%28%7B3%20-%205%7D%29%5E%7B2%7D%20%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B%20%28%7B%20-%205%7D%29%5E%7B2%7D%20%20%2B%20%28%20%7B%20-%202%7D%29%5E%7B2%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B25%20%2B%204%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B29%7D%20)
We have the final answer as
![\sqrt{29} \: \: \: or \: \: \:5.38 \: \: \: units](https://tex.z-dn.net/?f=%20%5Csqrt%7B29%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%20%5C%3A%20%20%5C%3A5.38%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20units)
Hope this helps you
Answer:
Where is the rest of the question
Step-by-step explanation:
Answer:
Step-by-step explanation: