Given:
The image of a lens crosses the x-axis at –2 and 3.
The point (–1, 2) is also on the parabola.
To find:
The equation that can be used to model the image of the lens.
Solution:
If the graph of polynomial intersect the x-axis at c, then (x-c) is a factor of the polynomial.
It is given that the image of a lens crosses the x-axis at –2 and 3. It means (x+2) and (x-3) are factors of the function.
So, the equation of the parabola is:
...(i)
Where, k is a constant.
It is given that the point (–1, 2) is also on the parabola. It means the equation of the parabola must be satisfy by the point (-1,2).
Putting
in (i), we get



Divide both sides by -4.


Putting
in (i), we get

Therefore, the required equation of the parabola is
.
Note: All options are incorrect.
The answer is they are all obtuse and all have a 100 degree angle
The answer:
r=2.745+8
r=10.745
Equation describes a sloping line. For any
equation ax+by+c = 0, slope is .<span>X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 30/5 = 6.Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 30/-3 = -10.Slope is -5/-3 = 1.66666666666667.<span> Equation in slope-intercept form: y=1.66666666666667*x+-10.</span></span>