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inn [45]
3 years ago
12

If you study hard, then you can pass the tests.

Mathematics
1 answer:
galina1969 [7]3 years ago
3 0
I think we all know it's A XD
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Help me pls! (Dot plots) Answer F G H. (Median and range)
skad [1K]

Answer:

F. Last season median was 2, this season median was 5

G. The range last season and this season are the same: 8

H. This season was Paula's best.  Her median score per game was 5, and she scored as many as 9 points in a game. (If you've discussed mean and mode in class, here's more info) Her mean score (average score) last season was 3.41, and this season was 5. Also, her mode (score she recorded most often) this season was 5, compared to last season's mode of 2.

Step-by-step explanation:

Last season data set:

0, 1, 1, 2, 2, 2, 2, 4, 5, 7, 7, 8

median: 2

range: 8 - 0 = 8

mean: 3.41 points per game

mode: 2 points per game

This season data set:

1, 2, 2, 3, 5, 5, 5, 5, 7, 8, 8, 9

median: 5

range: 9 - 1 = 8

mean: 5

mode: 5 points per game

Let me know if you have any questions.

8 0
3 years ago
A store is having a sale in which the cost of any item is 35% off. Which expression can be used to find the cost, x, of an item
Mekhanik [1.2K]

Answer:

73373773737477374747373738

3 0
3 years ago
PLEASE HELP ME<br> ( I WILL MARK BRAINLIEST )
AlekseyPX
The numbers are 15, 17 and 19
8 0
1 year ago
F(x) = x2 − x − ln(x) (a) find the interval on which f is increasing. (enter your answer using interval notation.) find the inte
Mekhanik [1.2K]

Answer:

(a) Decreasing on (0, 1) and increasing on (1, ∞)

(b) Local minimum at (1, 0)

(c) No inflection point; concave up on (0, ∞)

Step-by-step explanation:

ƒ(x) = x² - x – lnx

(a) Intervals in which ƒ(x) is increasing and decreasing.

Step 1. Find the zeros of the first derivative of the function

ƒ'(x) = 2x – 1 - 1/x = 0

           2x² - x  -1 = 0

     ( x - 1) (2x + 1) = 0

         x = 1 or x = -½

We reject the negative root, because the argument of lnx cannot be negative.

There is one zero at (1, 0). This is your critical point.

Step 2. Apply the first derivative test.

Test all intervals to the left and to the right of the critical value to determine if the derivative is positive or negative.

(1) x = ½

ƒ'(½) = 2(½) - 1 - 1/(½) = 1 - 1 - 2 = -1

ƒ'(x) < 0 so the function is decreasing on (0, 1).

(2) x = 2

ƒ'(0) = 2(2) -1 – 1/2 = 4 - 1 – ½  = ⁵/₂

ƒ'(x) > 0 so the function is increasing on (1, ∞).

(b) Local extremum

ƒ(x) is decreasing when x < 1 and increasing when x >1.

Thus, (1, 0) is a local minimum, and ƒ(x) = 0 when x = 1.

(c) Inflection point

(1) Set the second derivative equal to zero

ƒ''(x) = 2 + 2/x² = 0

             x² + 2 = 0

                   x² = -2

There is no inflection point.

(2). Concavity

Apply the second derivative test on either side of the extremum.

\begin{array}{lccc}\text{Test} & x < 1 & x = 1 & x > 1\\\text{Sign of f''} & + & 0 & +\\\text{Concavity} & \text{up} & &\text{up}\\\end{array}

The function is concave up on (0, ∞).

6 0
3 years ago
PLEASE HELP MEEEEeeeeeee
brilliants [131]

Step-by-step explanation:

Children have rights in order to ___________________________

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