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3 years ago

Solve the Equation p - 15 = 30.

Mathematics

2 answers:

kkurt [141]3 years ago

7 0

P + 45. add 15 to both sides.

Alina [70]3 years ago

5 0

Answer:

Step-by-step explanation:

add 15 on both sides

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The director of admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall sem

Sophie [7]

Answer:

Variance =10900.00

Standard deviation=104.50

Step by step Explanation:

Admissions Probability for 1100= 0.2

Admissions Probability for 1400=0.3

Admissions Probability for 1300 =0.5

To find the expected value, we will multiply each possibility by its probability and then add.

mean = 1100*0.2 + 1400*0.3 + 1300*0.5 = 1290

To find the variance, we will start by squaring each possibility and then multiplying it by its probability. We will then add these and subtract the mean squared.

E(X^2)=( 1100²*0.2)+ (1400²*0.3 )+ (1300²*0.5) = 1675000

Variance(X)=E(X²)- [E(X)]²

= 1675000 - (1290)²

=10900

Hence, the Variance(X)=10900

Then to calculate the standard variation , we will use the formular below,

standard variation (X)=√ var(X)= √10900

=104.5

Hence the standard variation=104.5

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3 years ago

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Aleks [24]

12.6 because it has to be the same as ED

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3 years ago

Read 2 more answers

(Note: a research study on coniferous trees of the American West

eimsori [14]

Answer:

p = 0.07

p-hat = 0.035

p0 = 0.07

p-value = 0.003

Step-by-step explanation:

p = population parameter, in this case, the rate of infestations across all trees in the forest

p-hat = test statistic, in this case, the rate of infestations found in the sample of trees, i.e. those in Doug's backyard

p0 = the null hypothesis, in this case, the rate of infestations within the forest is correctly evaluated at 0.07 or 7%

p-value = the likelihood any difference between p and p-hat is down to chance

In this case 0.003 as the p-value means there is only 0.3% probability of our statistic value of 0.035 being down to variability and chance meaning it is 99.7% likely that there is some reason behind this difference;

We would accept the alternative hypothesis which says the current parameter value, 0.07, is in fact incorrect (either too high or too low, in this case, likely too high).

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3 years ago

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3 years ago

a 34 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.137. find the substance's half-life, i

Ira Lisetskai [31]

Answer:

5.1 days

Step-by-step explanation:

Given in the question,

initial amount of substance = 34 grams

k-value = 0.137

To find the half life of this substance we will use following formula

$N(0)/2 = N(0)e^{-kt}$

here N(0) is initial amount of substance

t is time in days

Plug values in the formula

$34 /2 = 34e^{-0.137t}$

1/2 = e^{-0.137t}

Take logarithm on both sides

ln(1/2) = ln( e^{-0.137t})

ln(1/2) = -0.137t

t = ln(1/2) / -0.137

t = 5.059

t ≈ 5.1 days (nearest to tenths)

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3 years ago