Answer:

we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613
Step-by-step explanation:
The estimated proportion of interest is 
We need to find a critical value for the confidence interval using the normla standard distributon. For this case we have 95% of confidence, then the significance level would be given by
and
.
And the critical value is:
The confidence interval for the true population proportion is interest is given by this formula:

Replacing the values provided we got:

And we can conclude at 95% of confidence that the true proportion of interest for this case is between 0.287 and 0.613
Answer:
0.75,1,1.25
Step-by-step explanation:
increase in .25 every time.

Where r is the radius of the circle.
Answer:
20
Step-by-step explanation:
This is a binomial distribution
n = 100; p = 1/5
E(x) = np = (100)(1/5) = 20