Answer:
it's just 5 points LOLLLLL
Answer:
i dont want to put the whole example cz like ur school might catch u so u gonna have to do the explainin part srry:( but the answear is 156$
Step-by-step explanation:
Rhombus, Parallelogram, Kite, Rectangle, Square, Trapezoid, Isosceles Trapezoid
Answer:
Check the explanation
Step-by-step explanation:
(a)Let p be the smallest prime divisor of (n!)^2+1 if p<=n then p|n! Hence p can not divide (n!)^2+1. Hence p>n
(b) (n!)^2=-1 mod p now by format theorem (n!)^(p-1)= 1 mod p ( as p doesn't divide (n!)^2)
Hence (-1)^(p-1)/2= 1 mod p hence [ as p-1/2 is an integer] and hence( p-1)/2 is even number hence p is of the form 4k+1
(C) now let p be the largest prime of the form 4k+1 consider x= (p!)^2+1 . Let q be the smallest prime dividing x . By the previous exercises q> p and q is also of the form 4k+1 hence contradiction. Hence P_1 is infinite
To solve an addition problem, you simply add one number to the other. For example,
If I want to add 4 to 5, I would write the equation 4 + 5 = 9.
To solve a subtraction problem, you simply take a number away from another. For example,
If I want to take 5 away from 9, I would write the equation 9 - 5 = 4.
Hope I helped! :)
