Let the two numbers be x and y.
x + y = 86
+
x - y = 12
_________
2x + 0 = 98
__________
2x = 98
x = 98/2
x = 49
From x + y = 86
49 + y = 86
y = 86 - 49
y = 37
The numbers are 49 and 37.
Expand the brackets first
5(wx-v) = 9(x + v)
5wx - 5v = 9x + 9v
Get all x's on one side and everything on on the other side
9x - 5wx = 9v + 5v
factorise out the x
x(9-5w) = 14v
then divide by 9-5w
x = 14v/(9-5w)
9514 1404 393
Answer:
11.6 cm
Step-by-step explanation:
As the page title tells you, the Pythagorean theorem must be applied more than once. As you know, it tells you the square of the hypotenuse is the sum of the squares of the two sides.
AD² = ED² +EA²
EA² = AD²-ED² = 7² -6² = 13
EA = √13 ≈ 3.606
__
CD² = ED² +EC²
EC² = CD² -ED² = 10² -6² = 64
EC = √64 = 8
__
The length of the horizontal diagonal is ...
AC = EA +EC = 3.6 +8 = 11.6 . . . cm
It is given in the question that
Han wants to buy a $30 ticket to a game, but the pre order tickets are sold out. He knows there will be more tickets sold the day of the game, with a markup of 200%.
So Han expect to pay
for the ticket if he buys it the day of the game.
That is
