In the question, it is already given that the total number of runners in the race is 60 and out of them 1/3 dropped out in the first half. In the second half 1/4 of the remaining runners dropped out.
Now
Total number of runners in the race = 60
Number of runners that dropped out in the first half = 1/3 * 60
= 20
Number of runners remaining = 60 - 20
= 40
Number of runners dropping out in the second half = 40 * 1/4
= 10
Then the number of runners that finished the race = 40 - 10
= 30
Then 30 runners completed the race.
Answer:
Step-by-step explanation:
29 years they are combined ages the same and if this goes up 2:1 ratio every year thereafter from age 43 then to change 29:43 to make double it is x 8 43 x 8= 344 and 29 x16=464. The ages never become double.
20−6√3
Step by step Explanation:
√12+4√25−√108−1/4 √192
2√3+4×5-√108-2√3
2√3+20-√108-2√3
20−6√3
Let the difference between consecutive terms be D. If the middle term is 30, then the term before it is 30-D, and the term after it is 30+D. So the sum of these three terms would be (30-D) + 30 + (30+D) = 3*30.
Extending this sum to include all 11 terms centered around 30, we see that any addition of D is canceled by a balanced subtraction, leaving you with 11 copies of 30. So the value of the sum is 11*30 = 330.
