Answer: 
Step-by-step explanation:
The expanded form for the number 165.038 is 100+60+5+0.03+0.008.
<h3>What is the expended form of decimal numbers?</h3>
Writing decimals in expanded form simply means writing each number according to its place value. This is done by multiplying each digit by its place value and adding them together. Let's look at an example: 2.435. In words, we would say this as two and four hundred thirty-five thousandths.
In the given question expended form 100+60+5+30+8 is wrong.
After decimal point the first digit is at the tenth place and second digit at the hundredth place and third is at the thousandth place and so on....
165.038 = 100+60+5+
+
+
= 100+60+5+0.03+0.008
Hence, The correct expended form of the given number is 100+60+5+0.03+0.008.
To learn more about expended form from the given link:
brainly.com/question/603715
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You start with 2x -5>7 the you add five to both sides 2x-5+5>7 +5 2x.12 then divide both sides by 2 2x divided by 2 > and 12 divided by 2 and get x>6
We are asked to find the probability that a data value in a normal distribution is between a z-score of -1.32 and a z-score of -0.34.
The probability of a data score between two z-scores is given by formula
.
Using above formula, we will get:

Now we will use normal distribution table to find probability corresponding to both z-scores as:


Now we will convert
into percentage as:

Upon rounding to nearest tenth of percent, we will get:

Therefore, our required probability is 27.4% and option C is the correct choice.