To get a sum of 3, you must roll a 1 and a 2. To get a sum of 8, you must roll a 5 and 3, or two 4's.
There are two ways of rolling a 1 and a 2, two ways of rolling a 5 and a 3, and one way to roll two 4's.
There are

possible outcomes when rolling two such solids.
So the probability of getting a sum of 3 or 8 is
Answer:
27m^6n^12
Step-by-step explanation:
(3)^3 = 27
m^2^3 = m^6
n^4^3 = n^12
Answer:
x = 4
Step-by-step explanation:
Given the 2 equations
2x - y = 11 → (1)
x + 3y = - 5 → (2)
Multiply (1) by 3 and add to (2) to eliminate the y- term
6x - 3y = 33 → (3)
Add (2) and (3) term by term to eliminate y, that is
7x = 28 ( divide both sides by 7 )
x = 4
We need the options to help
Its is two since you take out the decimals then divide regularly