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3 years ago

What is the probability of the spinner landing on 2?

Mathematics

1 answer:

DiKsa [7]3 years ago

6 0

Answer:

the probability of the spinner landing on 2 is 25%

Step-by-step explanation:

if there are four different equal parts and there is one spinner

the probability of it landing on any of the parts is 25%

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Kyle and josh have a total of 64 CDs. Kyle has 12 mote than josh. How many CDs does each boy have?

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26 for Josh and 5th for kyle

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3 years ago

Raj’s bathtub is clogged and is draining at a rate of 1.5 gallons of water per minute. The table shows that the amount of water

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Raj’s bathtub is clogged and is draining at a rate of 1.5 gallons of water per minute. The table shows that the amount of water remaining in the bathtub, y, is a function of the time in minutes, x, that it has been draining.

What is the range of this function?

all real numbers such that y ≤ 40

all real numbers such that y ≥ 0

all real numbers such that 0 ≤ y ≤ 40

all real numbers such that 37.75 ≤ y ≤ 40

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2 years ago

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Write an addition and a subtraction expression, each with a value of 2.4x^10 -3

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2.01 is the right answer

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3 years ago

On the map of an amusement park on a coordinate grid, the skating rink is at (−0.5, −1).

Andrej [43]

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Step-by-step explanation:

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2 years ago

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The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

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3 years ago