What is the domain and range please?
1 answer:
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This is a 30-60-90 triangle. The short leg is given to us as 5
The long leg is equal to sqrt(3) times the short leg
long leg = sqrt(3)*(short leg)
long leg = sqrt(3)*5
long leg = 5*sqrt(3)
The base is 5. The height is 5*sqrt(3)
b = 5
h = 5*sqrt(3)
Use this to find the area
A = b*h/2
A = 5*5*sqrt(3)/2
A = 25*sqrt(3)/2
which is the exact area in terms of a radical
You can write it out as
The long leg is equal to sqrt(3) times the short leg
long leg = sqrt(3)*(short leg)
long leg = sqrt(3)*5
long leg = 5*sqrt(3)
The base is 5. The height is 5*sqrt(3)
b = 5
h = 5*sqrt(3)
Use this to find the area
A = b*h/2
A = 5*5*sqrt(3)/2
A = 25*sqrt(3)/2
which is the exact area in terms of a radical
You can write it out as
Answer: E is located at (-2, 6)
Explanation:
The rule for reflecting over y = x is
The x and y coordinates swap places.
Point E' is located at (6, -2) so that means point E must be located at (-2, 6)