2 years ago

Find the degree of the monomial: (-8a^7)^7

Mathematics

2 answers:

shtirl [24]2 years ago

7 0

Answer:

the degree is 49

Step-by-step explanation:

s344n2d4d5 [400]2 years ago

6 0

(-8a^7)^7

Simplify the exponents:

7 x 7 = 49

The degree is 49

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140 subtracted from the square of a number the result is three times the number find the negative solution

natima [27]

Answer:

$Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.$