The circumference of the outer edge of the path around the pool is 113.04 ft.
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What is the circumference?</h3>
The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.
Given
A circular swimming pool has a radius of 15 ft.
There is a path all the way around that pool that is three feet wide.
A circle has a radius of 15 feet.
A larger circle goes around the smaller circle that is 3 feet wide.
The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.
The radius of the outer edge of the path around the pool = 15 + 3
The radius of the outer edge of the path around the pool = 18ft
The circumference of the outer edge of the path around the pool is;

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.
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Sorry , idk .........................
Judging by the question at hand I generated this equation.
x+y=12
x=2y
I begin this question by plugging in the x=2y into the equation for x.
So the new equation should be 3y=12. I then divide the entire equation by 3 to get y=4.
Next I plug y=4 into the equation, the new equation should be x+4=12. I then subtract 4 from both sides to get x=8.
The two numbers are :
x=8 y=4
Answer:
y + 4 = (-1/6)(x - 6)
Step-by-step explanation:
Apply the point-slope formula here: y - k = m(x - h) becomes
y + 4 = (-1/6)(x - 6)