Solve for x.

Mathematics

1 answer:

Mademuasel [1]2 years ago

4 0

answer:x=5/3 because the is the easiest guess

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The square of a real number c is 8 less than the square of 6 show equation

juin [17]

Answer:

c^2 = 6^2 -8

Step-by-step explanation:

The square of c is c^2; the square of 6 is 6^2. for the former to be 8 less than the latter, we must have ...

c^2 = 6^2 -8

8 0

3 years ago

Rewrite in simplest radical form 1/x^-3/6

VladimirAG [237]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad

\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\quad \\
% rational negative exponent
a^{-\frac{{ n}}{{ m}}} =
 \cfrac{1}{a^{\frac{{ n}}{{ m}}}} \implies \cfrac{1}{\sqrt[{ m}]{a^{ n}}}
\\ \quad \\ \quad \\

% radical denominator
\cfrac{1}{\sqrt[{ m}]{a^{ n}}}= \cfrac{1}{a^{\frac{{ n}}{{ m}}}}\implies a^{-\frac{{ n}}{{ m}}}\qquad thus\\
----------------------------\\

\\ \quad \\

$ $\bf 
\\ \quad \\

\cfrac{1}{x^{-\frac{3}{6}}}\implies \cfrac{1}{x^{-\frac{1}{2}}}\implies \cfrac{1}{\frac{1}{x\frac{1}{2}}}\implies \cfrac{1}{1}\cdot \cfrac{x^{\frac{1}{2}}}{1}
\\ \quad \\
x^{\frac{1}{2}}\implies \sqrt{x}$