When one of them loses their job, their monthly income is reduced by $3,200. If they felt the need to file for bankruptcy, then the following statements is true?-

b. They could file for Chapter 7 bankruptcy and discharge most of their debt. (When one of the parent loses job, the median income will fall below the prescribed state median income, this is the reason they can file chapter 7 bankruptcy.)

4 0

2 years ago

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A basketball rim 10 ft high casts a shadow 15 ft long. at the same time, a nearby building casts a shadow that is 54 ft long. ho

Tatiana [17]

15/10= 3/2
54/x=3/2
3× what=54
18
18×2= 36 ft the building is 36 ft

7 0

2 years ago

Use Lagrange multipliers to find the maximum and minimum values of

marusya05 [52]

The Lagrangian is

$L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)$

It has critical points where the first order derivatives vanish:

$L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}$

$L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y$

$L_\lambda=x^2+y^2-4=0$

From the first two equations we get

$-\dfrac1{2x}=-\dfrac4y\implies y=8x$

Then

$x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}$

At these critical points, we have

$f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125$ (maximum)

$f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125$ (minimum)

5 0

3 years ago

Estelle drew two parallel lines PQ and R0S intersected by a transversal KL, as shown below: Which theorem could Estelle use to s

Sophie [7]

Angle KMQ and angle RNL are on apposite sides of the transversal and between above and below (exterior to) the parallel lines, so they are alternate exterior angles. Theorem - Alternate exterior angles formed by parallel lines and a transversal have the same measure.

8 0

2 years ago

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