Question

Roma selects cards from a standard of 52 cards. Once a card is selected, it is not replaced. Find the probability of each outcome.
a. a king of heart
b. a queen of spades
c. an ace of flower
d. an ace of diamond​

Answer 1

Given:

A card is selected randomly from a standard deck of 52 cards.

To find:

The probability of each outcome.

a. a king of heart

b. a queen of spades

c. an ace of flower

d. an ace of diamond​

Solution:

In a standard deck of 52 cards.

Total number of cards = 52

13 cards of each suit (heart, diamond, club, spade).

13 cards are Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King.

a. We need to find the probability of getting a king of heart.

Number of king of heart = 1

$P(\text{a king of heart})=\dfrac{\text{Number of king of heart}}{\text{Total cards}}$

$P(\text{a king of heart})=\dfrac{1}{52}$

b. We need to find the probability of getting a queen of spades.

Number of queen of spades = 1

$P(\text{a queen of spades})=\dfrac{\text{Number of queen of spades}}{\text{Total cards}}$

$P(\text{a queen of spades})=\dfrac{1}{52}$

c. We need to find the probability of getting an ace of flower (spades).

Number of ace of flower = 1

$P(\text{an ace of flower})=\dfrac{\text{Number of ace of flower}}{\text{Total cards}}$

$P(\text{an ace of flower})=\dfrac{1}{52}$

d. We need to find the probability of getting an ace of diamond​.

Number of ace of diamond​ = 1

$P(\text{an ace of diamond​})=\dfrac{\text{Number of ace of diamond​}}{\text{Total cards}}$

$P(\text{an ace of diamond​})=\dfrac{1}{52}$

Therefore, the required probabilities for each parts are:

(a) $\dfrac{1}{52}$

(b) $\dfrac{1}{52}$

(c) $\dfrac{1}{52}$

(d) $\dfrac{1}{52}$