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3 years ago

Pls...it’s due today

Mathematics

1 answer:

Marta_Voda [28]3 years ago

5 0

Answer:

70°

Step-by-step explanation:

Measure of the minor arc NM is 70° because measure of its corresponding central angle is 70°

You might be interested in

You are a personnel director and are interested in predicting the Number of Shares of Company Stock (Y) using the Number of Year

hoa [83]

Answer:

intercept=b0=75

Step-by-step explanation:

The least squares estimate of the intercept b0 can be computed as

b0=ybar-b1*xbar.

ybar=average number of shares of company stock=525.

xbar= average number of years employed=22.5.

slope=b1=20.

Thus,

intercept=b0=ybar-b1*xbar

intercept=b0=525-20*22.5

intercept=b0=525-450

intercept=b0=75.

Thus, the estimate of intercept b0=75.

8 0

3 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

3 years ago

How would I find x, I know it's an isosceles triangle but I so not know how to solve for it?????

Wittaler [7]

Answer:

x=7 (if your teacher cares it could + or - 7)

Step-by-step explanation:

Okay, since it's a 90 degree triangle you can use the Pythagorean theorem

( a^2 + b^2 = c^2)

Since it's an isosceles triangle the other side is x because it's the same value.

x^2 + x^2= (7 $\sqrt{2}$ )^2

Add the left side

2x^2= 7^2 + $\sqrt{2}$ ^2 roots and square roots cancel each other out

So -> 2x^2= 49 x 2 =98

just solve for x.

x^2 = 98/2

x^2= 49

Square root both sides

x= 7

3 0

3 years ago

Wayne and Garth are planning to have a concert. They have found two good options. Option 1: Malcolm's Music Hall will pay them $

storchak [24]

Answer:

50 people

Step-by-step explanation:

If you are to calculate the number of people that will come to the concert that will ensure option 1 and option 2 to yield equal amount

Let

x = number of people

Option 1:

Malcolm's Music Hall = 100 + 15x

Option 2:

Reggie's Reggae Room = 350 + 10x

Equate both options

100 + 15x = 350 + 10x

Collect like terms

100 - 350 = 10x - 15x

-250 = - 5x

x = -250/-5

x = 50 people

8 0

3 years ago

Please help me find the answer to:<br>12x^5 ÷ 3x^2

Ivahew [28]

Graph for 12*X^5/ (3*X^2)

4 0

2 years ago