X = k*y^2 * z
100 = 6^2*5*k,
k=0.555
x=0.555zy^2
x=o.555(8^2)(2)=71.1112.
Hope that helps!
<span>If 7 dancers were at a dance and 46 more came in and h left and there was 13 dancers left how many was h
</span>- h is 70.
The first thing I'll do is solve "5y = 2x + 20" for "<span>y=</span>", so that I can find my reference slope:
y = (2/5)x + 4;
So the reference slope from the reference line is <span>m = 2/5;</span>.
Now I need to find two new slopes, and use them with the point they've given me; namely, with the point (-1, 3). They want me to find the line through (4, –1) that is parallel to 5y = 2x + 20; that is, through the given point, they want me to find a line that has the same slope as the reference line.
Since a parallel line has an identical slope, then the parallel line through (-1, 3) will have slope <span>m = 2/5</span>. Now I have a point and a slope! So I'll use the point-slope form to find the line: y - 3 = (2/5)( x + 1);
Finally, y = (2/5)x + 17/5;
Answer:
there will be about less times than the cube earns!
Step-by-step explanation:
