Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
Answer:
Step-by-step explanation:
Just remember to divide the diameter by two to get the radius. If you were asked to find the radius instead of the diameter, you would simply divide 7 feet by 2 because the radius is one-half the measure of the diameter. The radius of the circle is 3.5 feet. You can also use the circumference and radius equation.
Answer:
1996
Step-by-step explanation:
To find the number of terms in an arithmetic sequence, divide the common difference into the difference between the last and first terms, and then add 1.
2008 - 13 = 1995 + 1 = 1996
We have that the fourth term of an arithmetic sequence is
a_4=14
Option C
From the question we are told
What is the fourth term of an arithmetic sequence whose first term is 23 and whose seventh term is 5?
A) 78
B) 32
C) 14
(Explain your work)
Generally the equation for the arithmetic sequence is mathematically given as
Therefore
For seventh term
Therefore
For Fourth term
a_4=14
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Answer:
See below in bold.
Step-by-step explanation:
You work in fractions of the city streets done per hour:
1/200 + 1/400 = 1 /x where x is the number of hours taken by 2 teams.
Multiply through by the LCM 400x:
2x + x = 400
3x = 400
x = 133.33 hours.
As there are 168 hours in a week they will have enough time.
