Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,

Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)

Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264

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Tags: <em>set theory divibilility divisible integers union intersection</em>
Answer:150
Step-by-step explanation:
0.15 x 1000
15/100 x 1000
(15 x 1000) ➗ (100 x 1)
15000 ➗ 100=150

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