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Elis [28]
1 year ago
13

2=-8-1x what’s the solution for x?

Mathematics
2 answers:
Veronika [31]1 year ago
5 0

Answer: The solution is x = -10

Step-by-step explanation:

Dahasolnce [82]1 year ago
3 0

∑ Hey, zzz413 ⊃

Answer:

x = -10

Step-by-step explanation:

<u><em>Given:</em></u>

<em>2=-8-1x</em>

<em>what’s the solution for x?</em>

<u><em>Solution:</em></u>

<em>Given that: 2=-8-1x</em>

<em>Add 8 to both sides</em>

<em>2 + 8 = -8 - x + 8</em>

<em>-x = 10</em>

<em>Divide both sides by -1</em>

<em>-x/-1 = 10/-1</em>

<em />

<em>x = -10</em>

<em />

<em>Hence, the solution for x is -10.</em>

<em />

<u><em>xcookiex12</em></u>

<u><em></em></u>

<em>8/23/2022</em>

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The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish?
Nata [24]

Answer: (not enough information) Is there a picture that goes along with the problem?

Step-by-step explanation:

3 0
2 years ago
I need help or I will faill this
kari74 [83]

Answer:

-4x2 + 3x - 225

 ———————————————

        3    

Step-by-step explanation:

Step  1  :

               4

Simplify   —

                3

Equation at the end of step  1  :

        4            

 (x -  (— • x2)) -  75

        3            

Step  2  :

Equation at the end of step  2  :

       4x2      

 (x -  ———) -  75

        3      

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a fraction from a whole

Rewrite the whole as a fraction using  3  as the denominator :

         x     x • 3

    x =  —  =  —————

         1       3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

x • 3 - (4x2)     3x - 4x2

—————————————  =  ————————

      3              3    

Equation at the end of step  3  :

 (3x - 4x2)    

 —————————— -  75

     3          

Step  4  :

Rewriting the whole as an Equivalent Fraction :

4.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

         75     75 • 3

   75 =  ——  =  ——————

         1        3    

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

  3x - 4x2  =   -x • (4x - 3)  

Adding fractions that have a common denominator :

5.2       Adding up the two equivalent fractions

-x • (4x-3) - (75 • 3)     -4x2 + 3x - 225

——————————————————————  =  ———————————————

          3                       3        

Step  6  :

Pulling out like terms :

6.1     Pull out like factors :

  -4x2 + 3x - 225  =   -1 • (4x2 - 3x + 225)  

Trying to factor by splitting the middle term

6.2     Factoring  4x2 - 3x + 225  

The first term is,  4x2  its coefficient is  4 .

The middle term is,  -3x  its coefficient is  -3 .

The last term, "the constant", is  +225  

Step-1 : Multiply the coefficient of the first term by the constant   4 • 225 = 900  

Step-2 : Find two factors of  900  whose sum equals the coefficient of the middle term, which is   -3 .

     -900    +    -1    =    -901  

     -450    +    -2    =    -452  

     -300    +    -3    =    -303  

     -225    +    -4    =    -229  

     -180    +    -5    =    -185  

     -150    +    -6    =    -156  

For tidiness, printing of 48 lines which failed to find two such factors, was suppressed

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Final result :

 -4x2 + 3x - 225

 ———————————————

        3        

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Answer:

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(ax^2 + 3x + 2b) - (5x^2+bx-3c)=  3x^2 - 9

First, move all to the left side.

(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0

Now let's group togheter terms with the same power of x.

(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.

This must be zero for all the values of x, then the things inside each parenthesis must be zero.

1)

a - 5 - 3 = 0

a = 3 + 5 = 8.

2)

3 - b = 0

b = 3.

3)

2b + 3c + 9 = 0

2*3 + 3c + 9 = 0

3c = -6 - 9 = -15

c = -15/3 = -5

Then we have:

a = 8, b = 3, c = -5

a + b + c = 8 + 3 - 5 = 6

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