The containers must be spheres of radius = 6.2cm
<h3>
How to minimize the surface area for the containers?</h3>
We know that the shape that minimizes the area for a fixed volume is the sphere.
Here, we want to get spheres of a volume of 1 liter. Where:
1 L = 1000 cm³
And remember that the volume of a sphere of radius R is:
Then we must solve:
![V = \frac{4}{3}*3.14*R^3 = 1000cm^3\\\\R =\sqrt[3]{ (1000cm^3*\frac{3}{4*3.14} )} = 6.2cm](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%2A3.14%2AR%5E3%20%3D%201000cm%5E3%5C%5C%5C%5CR%20%3D%5Csqrt%5B3%5D%7B%20%20%281000cm%5E3%2A%5Cfrac%7B3%7D%7B4%2A3.14%7D%20%29%7D%20%3D%206.2cm)
The containers must be spheres of radius = 6.2cm
If you want to learn more about volume:
brainly.com/question/1972490
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He multiplied rather than dividing.
Hope this helps!
It should be D: 35. 14 + 6 = 20. I just multiplied that by two, which equals 40. That means there are 2 sets of 14 and 2 sets of 6. Since there is 10 leftover, I divided both by 2. 7 + 3 = 10. 14 x 2 = 28 + 7 = 35
Answer:
a)12
b)1297.8( not sure for this)
c)77
d)1989
Step-by-step explanation:
12÷3+(4×2)
12÷3+8
4+8
12.
309×152÷(12×3)
309×152÷36
309×4.2
1297.8.
1988-1911
77
2021-(16×2)
2021-32
1989
if it helps don't forget to like and Mark me
Answer:
I'm guessing none because the discrimant (sqrt of b squared - 4ac is less than zero, signifying it has no real roots
Step-by-step explanation:
have a happy holidays!
