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3 years ago

Solve the following quadratic equation by using factorization and formula.

Mathematics

1 answer:

kenny6666 [7]3 years ago

6 0

Answer:

x=-7, -5

Step-by-step explanation:

x^2+12x+35=0

(X+5)(X+7)=0

x=-7, -5

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PLEASE PLEASE HELP ME WITH THIS PLEASE!!! ITS IXL

yarga [219]

Answer:

below

Step-by-step explanation:

The point N is at (-7, -8)

The point N’ is at (4, -4)

On the x-axis, -7 to 4 is a shift of 11 units to the right.

On the y-axis, -8 to -4 is a shift of 4 units upward.

To find the scale factor, we need to find the change in radius size.

As previously identified, the center of Circle N is (-7, -8). If we draw a vertical line from the center to the edge of the circle, the line will be 2 units long.

As previously identified, the center of Circle N’ is (-4, -4). If we draw a vertical line from the center to the edge of the circle, the line will be 6 units long.

6 is 3 times the amount of 2, meaning the scale factor is 3.

Hope this helps!

5 0

3 years ago

Read 2 more answers

Select the equation of a straight line that is parallel to the line 4y = 3x + 5.

Kisachek [45]

Answer:

Step-by-step explanation:

4y = 3x + 5 has a slope of 3/4

4y = 3x - 1 has a slope of 3/4

parallel lines have equal slopes

6 0

3 years ago

Read 2 more answers

If log10 C = y, then what does c equal?

Zigmanuir [339]

Answer:

$C = 10^y$

Step-by-step explanation:

By the definition of a log, $C = 10^y$

4 0

3 years ago

Tennis elbow is thought to be aggravated by the impact experienced when hitting the ball. The article "Forces on the Hand in the

Gnoma [55]

Answer:

Step-by-step explanation:

Hello!

The objective is to study whether there is a greater force after impacting on one- handed backhand drive in advanced tennis players than in intermediate tennis players.

Sample 1: Advanced tennis players

X₁: Force (N) on the hand just after impact on a one- handed backhand drive for an advanced tennis player.

n₁= 6

X[bar]₁= 40.29 N

S₁= 11.29

Sample 2: Intermediate players

X₂: Force (N) on the hand just after impact on a one- handed backhand drive for an intermediate tennis player.

n₂= 8

X[bar]₂= 21.40

S₂= 8.30

Assuming that both variables have a normal distribution and both population variances are equal, to compare these two populations is best to do so trough their population means using a t-test for independent samples.

If the force is greater for the advanced players than for the intermediate players, then you'd expect the population mean for the advanced players to be greater than the population mean for the intermediate players:

H₀: μ₁ ≤ μ₂

H₁: μ₁ > μ₂

α: 0.05

$t= \frac{(X_[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} } } ~~t_{n_1+n_2-2}$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{5*127.51+7*68.92}{6+8-2} }= 9.66$

$t_{H_0}= \frac{(40.29-21.40)-0}{9.66\sqrt{\frac{1}{6} +\frac{1}{8} } } = 3.62$

Using the p-value approach, the decision rule is

If p-value ≤ α, reject the null hypothesis

If p-value > α, do not reject the null hypothesis

The p-value for this test is 0.00024, it is less than the level of significance, so the decision is to reject the null hypothesis.

This means that at a 5% significance level you can conclude that the average force experienced on the hand after a one-handed backhand drive for advanced players is greater than the average force experienced on the hand after a one-handed backhand drive for intermediate players.

I hope this helps!

3 0

3 years ago

Katy finished 1/3 of her bag of Halloween candy in 3 days.How many days would it take for her to finish the entire bag of candy?

Lunna [17]

Answer:

Presuming she eats the same amount of sweets each day, 9 days

Step-by-step explanation

5 0

3 years ago