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1 year ago

Which verb form correctly completes this sentence?

Mathematics

1 answer:

Lorico [155]1 year ago

7 0

Es la letra C comprendan

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Is (2,3) a solution to the system of inequalities 4x+3y<20 <br> 10x+y>10

stiks02 [169]

Yes it is a solution because if you take the equation and plug the point in for the x and y :

4 (2) + 3 (3) < 20
8 + 9 < 20
17 < 20
which is true

10 (2) + (3) > 10
20 + 3> 10
23>10
which is also true

7 0

2 years ago

Read 2 more answers

Julia is going to the store to buy candies. Small candies cost $4 and extra-large candies cost $12.She needs to purchase at leas

BartSMP [9]

Answer:

Small candies $=9$

Extra large candies $=12$

Step-by-step explanation:

Let small candies $=x$

Extra large candies $=y$

the number of candies is at least $20$ .

$x+y\geq20$

Cost of $1$ small candy $=\$4$

Cost of $1$ extra large candy $=\$12$

but she has only $\$180$ to spend

$4x+12y\leq180$

Solve for

$x+y=20.......(1)\\4x+12y=180.....(2)\\eqn(2)-eqn(1)\times4\\8y=100\\y=\frac{100}{8} \\y=\frac{25}{8} \\from\ eqn(1)\\x+\frac{25}{2}=20\\ x=20-\frac{25}{2} \\x=\frac{15}{2}$

Since number of candies should be integer.

let $x=7,y=13$

total spend $4\times7+12\times13=184$ which is more than $\$180$ , so this combination is not possible.

$let\ x=8,y=12\\8\times4+12\times12=176$

She has $\$4$ more so she can buy $1$ more small candy.

Hence small candy $=9$

extra large candy $=12$

4 0

2 years ago

Three men are trying to hold a ferocious lion still for the veterinarian. The lion, in the center,is wearing a collar with three

Andre45 [30]

The answer
<span>the third rope to counterbalance Sam and Charlie is F
and vectF +vectF1 +vectF2 =vect0
let's consider axis
y'y </span>vectF = -F
vectF 1= F1cos60
vectF 2= F2cos45
-F = -F1cos60-F2co45
so F= F1cos60+F2co45= 350x0.5+400x0.7=457.84 pounds

4 0

2 years ago

Area of triangular prism

pychu [463]

I think the answer is 558.04

8 0

2 years ago

Help me find Sample variance and standard deviation

AnnZ [28]

First, find the mean. You'll need it to compute the variance.

$\bar x=\displaystyle\frac15\sum_{i=1}^5x_i=\dfrac{21+10+6+7+11}5=11$

The variance of the sample is then computed with the formula

$s^2=\displaystyle\dfrac1{5-1}\sum_{i=1}^5(\bar x-x_i)^2=\dfrac{(21-11)^2+\cdots+(11-11)^2}4=\dfrac{71}2=35.5$

The standard deviation is the square root of the variance, so

$s=\sqrt{35.5}\approx5.958$

5 0

2 years ago