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lidiya [134]
3 years ago
12

HELP ASAP

Mathematics
2 answers:
umka2103 [35]3 years ago
5 0

Answer:

1. 240

2. 600

3. 80

Step-by-step explanation:

In each problem, let x = unknown number

1. 30% of what number is 72?

0.3x = 72

x = 72/0.3

x = 240

Answer: 240

2. 10% of what number is 60?

0.1x = 60

x = 60/0.1

x = 600

Answer: 600

3. 70% of what number is 56?

0.7x = 56

x = 56/0.7

x = 80

Answer: 80

KengaRu [80]3 years ago
3 0

Answer:

<em><u>1. 240, 2. 600, 3. 80</u></em>

Step-by-step explanation:

1. In algebraic form, this is 3/10 * x = 72, which equals to x = 10/3 * 72, which is x = 240

Answer (1.) = 240

2. In algebraic form, this is 1/10 * x = 60, which equals to x = 10/1 * 60, which is x = 600

Answer (2.) = 600

3. In algebraic form, this is 7/10 * x = 56, which equals to x = 10/7 * 56, which is x = 80

Answer (2.) = 80

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Read 2 more answers
Which classification describes AMNO with vertices M(2, -3), N(3, 1), and<br> 0(-3, 1)?
Sonja [21]

Answer:

Option D

Step-by-step explanation:

32). Given vertices of the triangle are M(2, -3), N(3, 1) and O(-3. 1).

Distance between two points (x_1,y_1) and (x_2,y_2) is given by the expression,

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between M(2, -3) and N(3, 1) will be,

MN = \sqrt{(3-2)^2+(1+3)^2}

      = \sqrt{1+16}

      = \sqrt{17}

Distance between M(2, -3) and O(-3, 1),

MO = \sqrt{(2+3)^2+(-3-1)^2}

      = \sqrt{25+16}

      = \sqrt{41}

Distance between N(3, 1) and O(-3, 1),

NO = \sqrt{(3+3)^2+(1-1)^2}

      = 6

Condition for right triangle,

c² = a² + b² [Here c is the longest side of the triangle]

By this property,

MO² = MN² + NO²

(\sqrt{41})^2=(\sqrt{17})^2+6^2

41 = 17 + 36

41 = 51

False.

Therefore, given triangle is not a right triangle.

Since, length of all sides are not equal, given triangle will be a scalene triangle.

Option D is the correct option.

5 0
3 years ago
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