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Crank
3 years ago
8

A square has an area of 100 feet square. what is the length of each side

Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0

Answer:

10 ft

Step-by-step explanation:

area of square = side^2

A = s^2

We are told the area is 100 ft^2.

s^2 = 100 ft^2

Take the square root of both sides.

s = 10 ft

Answer: 10 ft

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Just answer the question below in the screenshot it!! Good luck!
8_murik_8 [283]

Answer:

it would be c

Step-by-step explanation:

4 0
3 years ago
Eya is 5 years younger than 3 times Bills age. If Eya is 28 how old is Bill?
Sedaia [141]
Bill's age = x

Eya's age = 3x - 5

Eya is 28

28 = 3x - 5

28 (+5) = 3x -5 (+5)

33 = 3x

33/3 = 3x/3

x = 11

Bill = x

x = 11

Bill is 11 years old

hope this helps
4 0
4 years ago
Please help on this one!! I need it in ASAP :(
lisov135 [29]

Answer:

Hey there! here's your answer

Step-by-step explanation:

Speed = distance/Time

Speed = 3/5 ÷ 1/2

Speed = 3/5 * 2

Speed = 6/5 mph or 1.2 mph.

5 0
3 years ago
Read 2 more answers
Help me find the volume of the composite figure
Butoxors [25]

Answer:

V = 97.911in^3

Step-by-step explanation:

Given

Shapes: Cube and Cone

Required

Determine the volume

First we calculate the volume of the cube

V_1 = l^3

Where

l = side length = 5.1

V_1 = 5.1^3

V_1 = 132.651

Next, calculate the volume of the cone using:

V_2 = \frac{\pi r^2h}{3}

Where

h = 5.1

r = \frac{1}{2} * Diameter

r = \frac{1}{2} * 5.1

r = 2.55

So, we have:

V_2 = \frac{\pi r^2h}{3}

V_2 = \frac{\pi * 2.55^2 * 5.1}{3}

V_2 = \frac{22 * 2.55^2 * 5.1}{7*3}

V_2 = \frac{729.5805}{21}

V_2 = 34.74

The volume of the figure is:

V=V_1 - V_2

V_1 = 132.651

V = 132.651 - 34.74

V = 97.911in^3

8 0
3 years ago
Suppose each runner ran at the rate given in the table above for 3.1 miles. How much time will elapse between the first place fi
Scilla [17]
You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:

Runner         distance           time

Arabella        7,299 feet        561 seconds
Bettina          3,425 yards     13 minutes, 12 seconds
Chandra       8,214 feet        0,195 hours
Divya            1,62 miles        732 seconds

To answer the question you must find the rate for each runner and then calculate the time to run 3.1 miles at each rate.

First you need to convert the data to obtain the rate in miles per second.

These are the main conversion identities:

1 mile = 5280 feet

1 mile = 1760 yards

1 hour = 3600 seconds

1 hour = 60 minutes

1 minute = 60 seconds

Arabella:

rate: 7,229 feet / 561 seconds * (1 mile / 5280 feet)  =

= 0.00244 mile/second

Time to run 3.1 miles: V = d / t => t = d / V = 3.1 miles / 0.00244 mile/second = 1270 seconds

Bettina:

13 minutes + 12 seconds = 13*60 seconds +12 seconds = 792 seconds

rate = 3425 yards / 792 seconds * 1 mile / 1760 yards = 0.00246 mile/seconds

Time to run 3.1 miles = 3.1 miles / 0.00246 mile/second = 1260 seconds

Chandra:

rate = 8214 feet / 0.195 hours * 1 mile / 5280 feet * 1hour / 3600 seconds =

= 0.00222 seconds

Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds

Divya:

rate = 1.62 miles / 732 seconds = 0.00221 seconds

Time = 3.1 mile / 0.00221 seconds = 1403 seconds

Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds

That is equivalent to 2.38 seconds.
6 0
3 years ago
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