Q10 A20 i think
hope this helps
Area=legnth times width
so multiply them together use distributive property
a(b+c)=ab+ac so
in this problem
(a+b)(c+d+e)=(a+b)(c)+(a+b)(d)+(a+b)(e)
so
x^2-2 times (2x^2-x+2)=(x^2)(2x^2-x+2)-(2)(2x^2-x+2)=(2x^4-x^3+2x^2)-(4x^2-2x+4)
add like terms
2x^4-x^3+(2x^2-4x^2)-2x+4
2x^4-x^3-2x^2-2x+4
Answer:
x = 5; y = 138, z= 42
Step-by-step explanation:
4x- 17 = 3 [ opposite sides of a parallelogram are equal]
4x = 3+ 17 = 20; X= 20/4 = 5
138 + Z = 180( angle on a straight line)
Z is an alternate angles to the remaining angle off 138 forming the straight line.
z= 180-138 = 42 degrees
Y = 138 [ opposite angles of a regular quadilareral been equal]
City C (42 and 66 are the two modes they are the most frequent numbers both appearing 3 times)
