Answer:
The object will reach its highest point 0.5 seconds after it has been thrown.
Step-by-step explanation:
The object reaches its maximum height when velocity is equal to zero, the velocity is the derivative of function height. That is:
(1)
Where
is the velocity of the object at time
, in feet per seconds.
If we know that
and
, then the time when object reaches its highest point is:
![v(t) = -32\cdot t+64](https://tex.z-dn.net/?f=v%28t%29%20%3D%20-32%5Ccdot%20t%2B64)
![-32\cdot t + 64 = 0](https://tex.z-dn.net/?f=-32%5Ccdot%20t%20%2B%2064%20%3D%200)
![t = 0.5\,s](https://tex.z-dn.net/?f=t%20%3D%200.5%5C%2Cs)
The object will reach its highest point 0.5 seconds after it has been thrown.
Answer:
Option (C)
Step-by-step explanation:
In the given circle, AB is a chord passing through the center O.
Therefore,chord AB is a diameter of the circle and OC is the radius.
AO = OB = OC
OC⊥AB, and length of OC = 7 cm
By applying Pythagoras theorem in right ΔBOC,
BC² = OC² + OB²
BC = ![\sqrt{OC^{2}+OB^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7BOC%5E%7B2%7D%2BOB%5E%7B2%7D%7D)
= ![\sqrt{7^2+7^2}](https://tex.z-dn.net/?f=%5Csqrt%7B7%5E2%2B7%5E2%7D)
=
≈ 9.9 units
Therefore, Option (C) will be the answer.
Do you have a picture?? Maybe? I’m not good at these
Not enough information- the coupon will only be worth 24% after tax though.